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我有一個下面的sql函數,它將一個字符串單詞作爲輸入,然後檢查單詞是否等於一個categoryName或不是我希望它的行爲像if語句爲true它從環打破,並否則返回0或1我該怎麼辦,即時通訊新的SQL腳本plz幫助返回@temp_catid ...以下是我的函數break和return @temp_catid if(true)
USE [myDB]
GO
/****** Object: UserDefinedFunction [dbo].[udfisEqualToCategory] Script Date: 01/31/2011 10:57:56 ******/
SET ANSI_NULLS ON
GO
SET QUOTED_IDENTIFIER ON
GO
Create FUNCTION [dbo].[udfisEqualToCategory](@word nvarchar(max))
RETURNS INT
AS
BEGIN
--declare a temp category table for data processing
declare @temptbl_category Table
(
indexx int identity(1,1),
categoryid int,
categoryname nvarchar(max)
)
--insert data from feedcrawler.category into temp category table
insert into @temptbl_category
select CategoryId,Name
from Category
--declare some variables to hold the data of current row of temp category table being processed while looping
declare @temp_catid int
declare @temp_catname nvarchar(max)
declare @rowcount int
set @rowcount=(select count(indexx)from @temptbl_category)
declare @I int
set @I=1
--print'given string-> '+ @FullName
--print'string length-> '+convert(nvarchar(max),@strlen)
while(@I <= @rowcount)
begin
select @temp_catname=categoryname,@temp_catid=categoryid from @temptbl_category where [email protected]
set @temp_catname=lower(@temp_catname)
if(@[email protected]_catname)
begin
return @temp_catid
break
end--end if
set @[email protected]+1
END--while loop ends
return 0
end-- function ends
GO
我知道省略標點符號可以節省我在輸入時的時間,但當他們讀取它時需要其他時間沒有冒犯只是一個觀察 – 2011-01-31 07:08:13