2017-12-27 187 views
0

我有一個REST回調服務必須按以下格式使用XML:Spring REST:適用於嵌套XML請求正文的構造函數嗎?

<SearchRequest> 
    <SearchCriteria> 
    <Param1></Param2> 
    <Param2></Param2> 
    </SearchCriteria> 
</SearchRequest> 

實際的XML具有「標準」的範圍內約32個參數,但是這給了基本思路。

我創建了一個SearchRequest類,它具有屬性searchCriteria和具有param1和param2的SearchCriteria類。

我的REST控制器類看起來是這樣的:

import org.springframework.beans.factory.annotation.Value; 
import org.springframework.http.HttpStatus; 
import org.springframework.http.ResponseEntity; 
import org.springframework.web.bind.annotation.RequestBody; 
import org.springframework.web.bind.annotation.RequestHeader; 
import org.springframework.web.bind.annotation.RequestMapping; 
import org.springframework.web.bind.annotation.RequestMethod; 
import org.springframework.web.bind.annotation.RestController; 

@RestController 
@RequestMapping("/acme/request/search") 
public class AcmeCallbackController { 
    @RequestMapping(method = RequestMethod.POST, consumes = "application/xml") 
    public ResponseEntity<String> postAcmeSearch(@RequestBody SearchRequest body) { 
     StringBuffer resultBuffer = new StringBuffer(2048); 
     // implementation code here, 'body' now expected to be a SearchRequest object contructed from request body XML 
     return new ResponseEntity<String>(resultBuffer.toString(), HttpStatus.OK); 
    } 

當我測試上面的服務,我收到以下錯誤響應:

`{ "timestamp": 1514390248822, 
"status": 400, 
"error": "Bad Request", 
"exception": org.springframework.http.converter.HttpMessageNotReadableException", 
"message": "JSON parse error: Can not construct instance of SearchRequest: no suitable constructor found, can not deserialize from Object value (missing default constructor or creator, or perhaps need to add/enable type information?); nested exception is com.fasterxml.jackson.databind.JsonMappingException: Can not construct instance of SearchRequest: no suitable constructor found, can not deserialize from Object value (missing default constructor or creator, or perhaps need to add/enable type information?)\n at [Source: [email protected]; line: 2, column: 3]", 
"path": "/acme/request/search" }` 

有誰知道合適的構造和/或註釋適用於SearchRequest,以便XML請求正確地反序列化?我在所有getter和setter上都有@JsonProperty(「{Attribute}」),其中{Attribute}是帶有初始上限以匹配XML元素名稱的屬性的名稱,以及一個爲每個屬性值。

TIA, 埃德

+0

你可以分享你的SearchRequest類,你有沒有在類中定義的任何參數化構造函數,如果是,那麼也添加默認構造函數。 –

+0

尋找JsonMappingExceptions的解決方案,就像https://stackoverflow.com/questions/7625783/jsonmappingexception-no-suitable-constructor-found-for-type-simple-type-class?rq=1,https:// stackoverflow .COM /問題/ 12750681 /不能-構建實例 - 的 - 傑克遜 – tkruse

回答

0

我想通了。我必須向構造函數參數添加註釋,例如

public SearchRequest(@JsonProperty("Param1") String param1, 
     @JsonProperty("Param2") String param2) { 
    this.param1 = param1; 
    this.param2 = param2; 
} 

它在那之後正常工作。