SQL查詢比較單個表中的行

Question

這裏我們比較基因表記錄：首先將基因a與所有基因a，b，c進行比較，例如aa，ab，ac同樣需要b然後ba，bb ，bc等.......

所以這裏匹配的結果是nd b是2，因爲匹配記錄是589,822 bc count的常用基因條件是1，因爲匹配記錄586和它應該是所有其他組合零。

goterm gene auto 
-------------------- 
589  a 1 
822  a 2 
478  a 3 
586  b 4 
589  b 5 
600  c 6 
586  c 7 
822  b 8 

查詢：

select count(*), 
     x.gene, 
     x.ng 
from (select t.gene, 
       v.gene as ng 
     from (select distinct gene 
       from gene) as t 
    cross join (select distinct gene from gene) as v) as x 
    left join (select (g.gene),(n.gene) as ng from gene g 
     join gene n on n.goterm=g.goterm where g.auto<n.auto) as y on y.gene = x.ng 
                    and y.ng = x.gene 
group by x.gene,x.ng 

最後上面查詢的輸出是：

count gene gene 
1  a  a 
2  b  a 
1  c  a 
1  a  b 
1  b  b 
1  c  b 
1  a  c 
1  b  c 
1  c  c 

但輸出必須：

count gene gene 
0  a  a 
2  b  a 
0  c  a 
0  a  b 
0  b  b 
1  c  b 
0  a  c 
0  b  c 
0  c  c 

Answer 1

select combo1.gene, combo2.gene, count (gene2.goterm) 
from (select distinct gene from gene) combo1 
cross join (select distinct gene from gene) combo2 
join gene gene1 on combo1.gene = gene1.gene 
left join gene gene2 on combo2.gene = gene2.gene 
    and gene1.goterm = gene2.goterm and gene1.auto < gene2.auto 
group by combo1.gene, combo2.gene 
order by combo1.gene, combo2.gene 

編輯：意識到畢竟我並不需要DISTINCT。

Answer 2

不知道究竟怎麼了你邏輯起作用（特別是c在auto ompare），但這個查詢產生你正在尋找的結果是：

declare @t table (goterm int, gene char(1), auto int identity) 
insert @t 
      select 589,  'a' 
union select all 822,  'a' 
union select all 478,  'a' 
union select all 586,  'b' 
union select all 589,  'b' 
union select all 600,  'c' 
union select all 586,  'c' 
union select all 822,  'b' 

select t1.gene 
,  t2.gene 
,  (
     select COUNT(*) 
     from @t t3 
     join @t t4 
     on  t3.goterm = t4.goterm 
       and t3.auto > t4.auto 
     where t3.gene = t1.gene 
       and t4.gene = t2.gene 
     ) as Total 
from (
     select distinct gene 
     from @t 
     ) t1 
cross join 
     (
     select distinct gene 
     from @t 
     ) t2 
order by 
     t2.gene 
,  t1.gene 

此打印：

gene gene Total 
a  a  0 
b  a  2 
c  a  0 
a  b  0 
b  b  0 
c  b  1 
a  c  0 
b  c  0 
c  c  0 

的t1和t2在那裏創建基因組合的矩陣。 Total查詢查找該組合的點擊次數。 t3.auto > t4.auto的情況讓我困惑，所以你可能要仔細檢查一下。

Answer 3

嘗試在您的查詢中更改count(*)至count(y.gene)。