Symfony的形式收集排序依據從一對多關係的領域從多對一

Question

一個棘手的一點：

我有一個表格集合實體Street。 收集項目是houses。我需要的room

下令集合中的房子我已經嘗試添加@ORM\OrderBy({"room" = "ASC"})但顯然沒有指定客房內實體的重量領域是沒有辦法的收集就知道了。

我試圖做甚至可能嗎？

Street.php

/** 
* @var ArrayCollection 
* 
* @ORM\OneToMany(targetEntity="houses", mappedBy="street") 
*/ 
protected $houses; 

Houses.php

/** 
* @var Room 
* 
* @ORM\ManyToOne(targetEntity="Room", inversedBy="house") 
* @ORM\JoinColumn(name="room_id", referencedColumnName="id") 
*/ 
private $room; 

/** 
* @var Street 
* 
* @ORM\ManyToOne(targetEntity="Street", inversedBy="houses") 
* @ORM\JoinColumn(name="street_id", referencedColumnName="id") 
*/ 
private $street; 

HouseCollectionType.php

$builder 
     ->add('houses', 'collection', array(
      'type'   => new HouseFieldsType(), 
      'allow_delete' => false, 
     )) 
    ; 

public function setDefaultOptions(OptionsResolverInterface $resolver) 
    { 
    $resolver->setDefaults(array(
     'data_class' => 'Bundle/Street' 
    )); 
    } 

Answer 1

我不知道這是否是正確的做法，但這裏有雲：

Street.php

public function getHouses() 
{ 
    $orderedHouse = array(); 
    /** @var House $house */ 
    foreach($this->houses as $house) { 
     $orderedHouses[$house->getRoom()->getWeight()] = $house; 
     $this->houses->removeElement($house); 
    } 
    ksort($orderedHouses); 
    foreach($orderedHouses as $house) { 
     $this->houses->add($house); 
    } 
    return $this->houses; 
}