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我是新來的easyadmin包，我期待它是否可以直接從父對象 增加孩子的，所以我就3個對象： - 配方symfony的easyadmin一對多的形式
namespace AppBundle\Entity;
use Doctrine\ORM\Mapping as ORM;
/**
* Recipe
*
* @ORM\Table(name="recipe")
* @ORM\Entity(repositoryClass="AppBundle\Repository\RecipeRepository")
*/
class Recipe
{
/**
* @var int
*
* @ORM\Column(name="id", type="integer")
* @ORM\Id
* @ORM\GeneratedValue(strategy="AUTO")
*/
private $id;
/**
* @var string
*
* @ORM\Column(name="name", type="string", length=100, nullable=true)
*/
private $name;
/**
* @var \DateTime
*
* @ORM\Column(name="createdon", type="datetime", nullable=true)
*/
private $createdon;
/**
* @var string
*
* @ORM\Column(name="description", type="text", nullable=true)
*/
private $description;
/**
* @var string
*
* @ORM\Column(name="version", type="string", length=5, nullable=true)
*/
private $version;
/**
* @ORM\OneToMany(targetEntity="Recipe_Product", mappedBy="recipe")
*/
private $recipeproducts;
...
- Recipe_Product（其具有作爲屬性輸入量和單位）
namespace AppBundle\Entity;
use Doctrine\ORM\Mapping as ORM;
/**
* Recipe_Product
*
* @ORM\Table(name="recipe__product")
* @ORM\Entity(repositoryClass="AppBundle\Repository\Recipe_ProductRepository")
*/
class Recipe_Product
{
/**
* @var int
*
* @ORM\Column(name="id", type="integer")
* @ORM\Id
* @ORM\GeneratedValue(strategy="AUTO")
*/
private $id;
/**
* @var string
*
* @ORM\Column(name="quantity", type="decimal", precision=10, scale=2, nullable=true)
*/
private $quantity;
/**
* @ORM\ManyToOne(targetEntity="Recipe", inversedBy="recipeproducts")
* @ORM\JoinColumns({
* @ORM\JoinColumn(name="recipeid", referencedColumnName="id")
* })
*/
private $recipe;
/**
* @ORM\ManyToOne(targetEntity="Product", inversedBy="recipeproducts")
* @ORM\JoinColumns({
* @ORM\JoinColumn(name="Productid", referencedColumnName="id")
* })
*/
private $product;
/**
* @ORM\ManyToOne(targetEntity="Unit", inversedBy="recipeproducts")
* @ORM\JoinColumns({
* @ORM\JoinColumn(name="Unitid", referencedColumnName="id")
* })
*/
private $unit;
...
，當然是一個 - 產品。
namespace AppBundle\Entity;
use Doctrine\ORM\Mapping as ORM;
/**
* Product
*
* @ORM\Table(name="product")
* @ORM\Entity(repositoryClass="AppBundle\Repository\ProductRepository")
*/
class Product
{
/**
* @var int
*
* @ORM\Column(name="id", type="integer")
* @ORM\Id
* @ORM\GeneratedValue(strategy="AUTO")
*/
private $id;
/**
* @var string
*
* @ORM\Column(name="name", type="string", length=255)
*/
private $name;
/**
* @var string
*
* @ORM\Column(name="ref", type="string", length=25)
*/
private $ref;
/**
* @var string
*
* @ORM\Column(name="ref4stat", type="string", length=25)
*/
private $ref4Stat;
/**
* @var int
*
* @ORM\Column(name="size", type="integer")
*/
private $size;
/**
* @ORM\ManyToOne(targetEntity="Unit", inversedBy="products")
* @ORM\JoinColumns({
* @ORM\JoinColumn(name="unitid", referencedColumnName="id")
* })
*/
private $unit;
/**
* @ORM\ManyToOne(targetEntity="ProductType", inversedBy="products")
* @ORM\JoinColumns({
* @ORM\JoinColumn(name="producttypeid", referencedColumnName="id")
* })
*/
private $producttype;
/**
* @ORM\OneToMany(targetEntity="Recipe_Product", mappedBy="product")
*/
private $recipeproducts;
...
當編輯配方，我想能夠直接添加新recipe_product線，但我避風港t上找不到一種方式來做到這一點...
任何人有一個想法？
添加於14/10： 我找到了一種方法來呈現形式...... 我easyadmin配置文件，我創建了以下條目：
Recipe:
class: AppBundle\Entity\Recipe
form:
fields:
- name
- beer
- version
- description
- createdon
- { property: 'recipeproducts', label: 'Ingredients', type: 'collection', type_options: {entry_type: 'AppBundle\Form\Recipe_ProductType', by_reference: false} }
與表單代碼爲
<?php
namespace AppBundle\Form;
use Symfony\Component\Form\AbstractType;
use Symfony\Component\Form\FormBuilderInterface;
use Symfony\Component\OptionsResolver\OptionsResolver;
use Symfony\Component\Form\Extension\Core\Type\HiddenType;
class Recipe_ProductType extends AbstractType
{
/**
* @param FormBuilderInterface $builder
* @param array $options
*/
public function buildForm(FormBuilderInterface $builder, array $options)
{
$builder
->add('product')
->add('quantity')
->add('unit')
;
}
/**
* @param OptionsResolver $resolver
*/
public function configureOptions(OptionsResolver $resolver)
{
$resolver->setDefaults(array(
'data_class' => 'AppBundle\Entity\Recipe_Product'
));
}
}
這使得形式（即不要噸創建2個實體之間的鏈接，但必須是在管理控制器我想）