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我偶爾看到一個數據包被我的udp多播接收器接收兩次。我設置多播客戶端如下:.NET UDP多播接收
private static void setupUdpMulticastClient()
{
//IPEndPoint ipRXEnd = new IPEndPoint(IPAddress.Any,multicastPort);
IPEndPoint ipRXEnd = new IPEndPoint(IPAddress.Parse(emulatorIpaddr), multicastPort);
udpMulticastClient = new UdpClient();
udpMulticastClient.Client.ExclusiveAddressUse = false;
udpMulticastClient.Client.SetSocketOption(SocketOptionLevel.Socket, SocketOptionName.ReuseAddress, true);
udpMulticastClient.Client.Bind(ipRXEnd);
}
emulatorIpaddr是一個192.x.x.x地址。
接收器看起來如下:
public static void MulticastSetBeginReceive()
{
//IPAddress ipSSDP = IPAddress.Parse(multicastIP);
IPAddress ipSSDP = IPAddress.Parse(emulatorIpaddr);
IPEndPoint ipRXEnd = new IPEndPoint(ipSSDP, multicastPort);
UdpState udpListener = new UdpState();
udpListener.e = ipRXEnd;
if (udpMulticastClient == null)
{ setupUdpMulticastClient();}
udpListener.u = udpMulticastClient;
udpMulticastClient.BeginReceive(new AsyncCallback(MulticastReceiveCallback), udpListener);
}
這似乎觸發異步回調上occassion 2倍。爲了完整起見, 這裏是回調代碼:
public static void MulticastReceiveCallback(IAsyncResult ar)
{
try
{
UdpClient u = (UdpClient)((UdpState)(ar.AsyncState)).u;
IPEndPoint e = (IPEndPoint)((UdpState)(ar.AsyncState)).e;
if (u.Client != null)
{
Byte[] receiveBytes = u.EndReceive(ar, ref e);
string receiveString = Encoding.ASCII.GetString(receiveBytes);
string from = e.ToString();
string to = ((UdpState)(ar.AsyncState)).e.ToString();
msgReceiver(DateTime.Now.ToLocalTime(), from, to, receiveString);
}
if (running)
MulticastSetBeginReceive();
}
catch (Exception ex)
{
log.Debug(ex.Message);
log.Debug(ex.StackTrace);
}
}
我運行Windows 7和.Net 4
有誰看到代碼中的問題,或者知道使用.NET的一個問題或贏得7分,這將導致這種行爲。