//Add comments here that explain the Sqrt method
private void btnSqrt_Click(object sender, EventArgs e)
{
double num = double.Parse(textDisplay.Text);
if (num >= 0)
{
public class Sqrt
{
public static void main(String[] args)
{
double EPS = 1E-15;
double c = Double.parseDouble(args[0]);
double t = c;
while (Math.abs(t -
我的代碼不會運行我得到的錯誤「無法在原始類型double上調用sqrt(double)」這就是我編譯它時得到的唯一錯誤,否則除Math.sqrt(數學)行外不會導致錯誤。幫幫我? public class Confused {
public static double average(int x, int y) {
double ave= (x+y)/2.0;
return ave;
}
我想在彙編中編寫一個快速整數平方根算法,它採用無符號32位。我一直在閱讀this,並有一個想法。這裏是我的僞代碼: res <- 0
for i from 15 downto 0 do:
change the ith bit of result to 1
if res^2 > x then:
change the ith bit of res back to 0