我需要在SQL Server 2014中加入下面兩個表格,我使用了下面的代碼,但是我的問題是Sales_org不匹配。如果它不匹配,它應該返回一個基於Material而不是Sales Organization的值。 它是0的原因是兩個國家都是一樣的。 Left Join
[Z_PACKING] on [CTE_OPMAO2].[Material] = [Z_PACKING].[Material
下面是我的SQL語法,如何實現它在laravel,在此先感謝。 SELECT * FROM `tr_policy_privacy` AS pri
LEFT JOIN
(SELECT * FROM tr_policy_full_create as cri WHERE cri.client_id=156 and cri.policy_type_id = 1)
AS hours
ON pri.i
我想加入3個表中類似如下的方式: SELECT a.id
FROM tableA AS a
LEFT JOIN tableB AS b ON a.id = b.id
LEFT JOIN tableC AS c ON a.id = c.id
WHERE
b.name = c.name OR b.name IS NULL OR c.name IS NULL;
我不能肯定,該表B或C將有行