假設我有這個可變參數的基類模板: template <typename ... Types>
class Base
{
public:
// The member foo() can only be called when its template
// parameter is contained within the Types ... pack.
tem
我遇到了關於enable_if和模板特化的正確使用的問題。 修改的例子(出於保密原因)後,這裏有一個可比的例子: I have function called "less" that checks if 1st arg is less than 2nd arg. Let's say I want to have 2 different kinds of implementations depend
這個代碼在VS2013和其他編譯器使用enable_if和underlying_type在函數簽名(測試鐺3.4和gcc 4.8),但未能在VS2012編譯: #include <type_traits>
#include <cstdio>
// error C4519: default template arguments are only allowed on a class templ