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我有一個名爲「obj」的類,它有兩個數據類型一個int和一個double。我試圖只讀第三個對象,但似乎無法弄清楚。在我將其中一種數據類型改爲兩倍之前,它正在工作。我覺得它與類型匹配有關。總結起來,我不能得到它只輸出第三個對象後,文件已經wrriten。有什麼建議麼?輸出一個二進制文件寫入C++
#include<iostream>
#include<fstream>
using namespace std;
class Data {
public:
int num1;
double num2;
Data() {}
~Data() {}
void setData();
void getData();
};
void Data::getData()
{
cout << "Enter first number: ";
cin >> num1;
cout << "Eneter second number: ";
cin >> num2;
}
#include "class.h"
const int SIZE = 5;
int main()
{
Data obj[SIZE];
for (int i = 0; i < SIZE; i++)
{
cout << "Enter numbers of object " << i+1 << endl;
obj[i].getData();
}
ofstream outFile;
outFile.open("C:\\Users\\juan\\Desktop\\26.bin", ios::out | ios::binary);
for (int i = 0; i < SIZE; i++)
{
outFile.write(reinterpret_cast<char *> (&obj[i].num1), sizeof(obj[i].num1));
outFile.write(reinterpret_cast<char *> (&obj[i].num2), sizeof(obj[i].num2));
}
cout << "Writing to file...." << endl;
outFile.close();
ifstream inFile;
inFile.open("C:\\Users\\juan\\Desktop\\26.bin", ios::in | ios::binary);
for (int i = 0; i < SIZE; i++)
{
inFile.read(reinterpret_cast<char *> (&obj[i].num1), sizeof(obj[i].num1));
inFile.read(reinterpret_cast<char *> (&obj[i].num2), sizeof(obj[i].num2));
}
for (int i = 0; i < SIZE; i++)
{
cout << obj[i].num1 << endl;
cout << obj[i].num2 << endl;
cout << endl << endl;
}
inFile.close();
Data third;
fstream seekfile;
seekfile.open("C:\\Users\\juan\\Desktop\\26.bin", ios::in | ios::binary);
seekfile.seekg(2 * sizeof(Data), ios::beg);
seekfile.read(reinterpret_cast<char *> (&third.num1), sizeof(third.num1));
seekfile.read(reinterpret_cast<char *> (&third.num2), sizeof(third.num2));
cout << endl << endl;
cout << third.num1 << endl;
cout << third.num2 << endl;
seekfile.close();
}
建議:1)讓我們確切地知道什麼是不工作。它是編譯錯誤,運行時錯誤還是意外結果? 2)問一個比「任何建議?」更好的問題? – user463035818
它不輸出第三個對象只給我我認爲是一個內存空間 – juanmindset
什麼是'數據'的定義? – Peter