我正在使用spring-mvc 3.1.1.RELEASE和Spring-Security構建一個應用程序,我希望每個人都必須登錄才能訪問它,同時我想限制訪問通過角色的一些用戶,我編輯了彈簧的security.xml這樣:Spring mvc和基於安全角色的限制問題
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:context="http://www.springframework.org/schema/context"
xmlns:sec="http://www.springframework.org/schema/security"
xsi:schemaLocation="http://www.springframework.org/schema/beans
http://www.springframework.org/schema/beans/spring-beans-3.1.xsd
http://www.springframework.org/schema/security
http://www.springframework.org/schema/security/spring-security-3.1.xsd
http://www.springframework.org/schema/context
http://www.springframework.org/schema/context/spring-context-3.1.xsd">
<bean id="userDetailsService" class="it.dedagroup.cartesio.security.auth.UserDetailServiceImpl">
<property name="accountService" ref="accountService"></property>
</bean>
<sec:http auto-config="true" use-expressions="true" create-session="always">
<sec:http-basic />
<sec:intercept-url pattern="/login" access="permitAll"/>
<sec:intercept-url pattern="/failedLogin" access="permitAll"/>
<sec:intercept-url pattern="/resources/**" access="permitAll"/>
<sec:intercept-url pattern="/error" access="permitAll"/>
<sec:intercept-url pattern="/accessDenied*" access="isAuthenticated()" />
<sec:intercept-url pattern="/home*" access="isAuthenticated()" />
<sec:intercept-url pattern="/utentiRicerca*" access="hasRole('ROLE_ADMIN')" />
<sec:intercept-url pattern="/userEdit*" access="hasRole('ROLE_ADMIN')" />
<sec:intercept-url pattern="/creaUser*" access="hasRole('ROLE_ADMIN')" />
<sec:intercept-url pattern="/detailsUtente*" access="isAuthenticated()" />
<sec:intercept-url pattern="/modificaAccount*" access="isAuthenticated()" />
<sec:intercept-url pattern="/serverRicerca*" access="hasRole('ROLE_ADMIN')" />
<sec:intercept-url pattern="/editServer*" access="hasRole('ROLE_ADMIN')" />
<sec:intercept-url pattern="/prepareListaSearch*" access="hasRole('ROLE_ADMIN')" />
<sec:intercept-url pattern="/prepareListaEdit*" access="hasRole('ROLE_ADMIN')" />
<sec:intercept-url pattern="/groupInitSearch*" access="hasRole('ROLE_ADMIN')" />
<sec:intercept-url pattern="/groupEdit*" access="hasRole('ROLE_ADMIN')" />
<sec:intercept-url pattern="/listaUpdate*" access="hasRole('ROLE_ADMIN')" />
<sec:intercept-url pattern="/upload*" access="isAuthenticated()" />
<sec:intercept-url pattern="/emailRicerca*" access="hasRole('ROLE_ADMIN')" />
<sec:intercept-url pattern="/prepareEditCasella*" access="hasRole('ROLE_ADMIN')" />
<sec:intercept-url pattern="/acl*" access="hasRole('ROLE_ADMIN')" />
<sec:intercept-url pattern="/initDaemons*" access="hasAnyRole('ROLE_ADMIN','ROLE_SYSTEM')" />
<sec:intercept-url pattern="/mailbox*" access="hasAnyRole('ROLE_OPER','ROLE_USER')" />
<sec:intercept-url pattern="/emailBody*" access="hasAnyRole('ROLE_OPER','ROLE_USER')" />
<sec:intercept-url pattern="/pecBody*" access="hasAnyRole('ROLE_OPER','ROLE_USER')" />
<sec:intercept-url pattern="/composeEmail*" access="hasRole('ROLE_OPER')" />
<sec:form-login login-page="/login"
always-use-default-target="true"
default-target-url="/home"
authentication-failure-url="/failedLogin" />
<sec:logout invalidate-session="true" logout-success-url="/logout" delete-cookies="true" />
<sec:session-management invalid-session-url="/login" session-authentication-error-url="/failedLogin?sessionExpiredDuplicateLogin=true" >
<sec:concurrency-control max-sessions="1" expired-url="/failedLogin" error-if-maximum-exceeded="false" />
</sec:session-management>
</sec:http>
<sec:authentication-manager>
<sec:authentication-provider user-service-ref="userDetailsService">
<sec:password-encoder ref="stdEncoder"></sec:password-encoder>
</sec:authentication-provider>
</sec:authentication-manager>
,但如果我刪除根URL的seurity映射,它返回了我未找到頁面錯誤,如果我以這種方式評價安全性:
<sec:intercept-url pattern="/**" access="isAuthenticated()" />
它在登錄後包裝了我所有的請求,並忽略了我直接在瀏覽器欄上寫入時爲子網址指定的規則。
例如,我需要只有「ROLE_ADMIN」才能訪問URL「/ utentiRicerca」處的用戶搜索,但是如果我使用「ROLE_USER」登錄並在瀏覽器URL「http://myhost.it:8080/myApp/utentiRicerca」上寫入,它不會給我「 http 403「,因爲我配得上這個角色。那麼我能爲它做些什麼?
確保'/ **'的mappnig是你鏈中的最後一個。他們按照指定的順序查詢,所以如果'/ **'是第一個餘數未被使用。第一個匹配模式被使用。 – 2014-11-14 12:36:14