通過在Java中使用

Question

文件快速排序排序

目前我已經通過文件迭代，但現在我想用快速排序的排序輸出。我創建了一個與本地數組一起工作的quickSort/partition類，但我想知道如何將它與其他類中的文件一起使用。我想做一些事情，比如按人口排序，按字母順序排列城市，按緯度排序。

這裏是一些文件是我的工作：

ad,Andorra La Vella,07,20430,42.5,1.5166667 
ad,Canillo,02,3292,42.5666667,1.6 
ad,Encamp,03,11224,42.5333333,1.5833333 
ad,La Massana,04,7211,42.55,1.5166667 
ad,Les Escaldes,08,15854,42.5,1.5333333 
ad,Ordino,05,2553,42.55,1.5333333 
ad,Sant Julia De Loria,06,8020,42.4666667,1.5 
ae,Abu Dhabi,01,603687,24.4666667,54.3666667 
ae,Dubai,03,1137376,25.2522222,55.28 

我的代碼：

public class City { 
    String countrycode; 
    String city; 
    String region; 
    int population; 
    double latitude; 
    double longitude; 

    public City(String countrycode, String city, String region, int population, double latitude, double longitude) { 
     this.countrycode = countrycode; 
     this.city = city; 
     this.region = region; 
     this.population = population; 
     this.latitude = latitude; 
     this.longitude = longitude; 
    } 

    public String toString() { 
     return this.city + "," + this.population + "," + this.latitude + "," + this.longitude; 
    } 
} 

public class Reader { 

    In input = new In("file:world_cities.txt"); 
    public static City cityInfo; 

    public static void main(String[] args) { 
     // open file 
     In input = new In("world_cities.txt"); 

     try { 
      // write output to file 
      FileWriter fw = new FileWriter("cities_out.txt"); 
      PrintWriter pw = new PrintWriter(fw); 

      int line = 0; 

      // iterate through all lines in the file 
      while (line < 47913) { 

       // read line 
       String cityLine = input.readLine(); 

       // create array list 
       ArrayList<String> cityList = new ArrayList<String>(Arrays.asList(cityLine.split(","))); 

       // increase counter 
       line += 1; 

       // create variables for the object 
       String countrycode = cityList.get(0); 
       String city = cityList.get(1); 
       String region = cityList.get(2); 
       int population = Integer.parseInt(cityList.get(3)); 
       double latitude = Double.parseDouble(cityList.get(4)); 
       double longitude = Double.parseDouble(cityList.get(5)); 
       // create instance 
       cityInfo = new City(countrycode, city, region, population, latitude, longitude); 
       System.out.println(cityInfo); 

       // print output to file 
       pw.println(cityInfo); 
      } 

      // close the file 
      pw.close(); 
     } 

     // what is printed when there is an error when saving to file 
     catch (Exception e) { 
      System.out.println("ERROR!"); 
     } 

     // close the file 
     input.close(); 
    } 
} 

public class QuickSort3 { 
    public static void main(String[]args) { 
     int[] array = {4, 77, 98, 30, 20, 50, 77, 22, 49, 2}; // local array that works with the quicksort 
     quickSort(array,0,array.length - 1); 
     System.out.println(Arrays.toString(array)); 
    } 

    public static void quickSort(int[] a, int p, int r) 
    { 
     if(p<r) 
     { 
      int q = Partition(a, p,r); 
      quickSort(a, p, q-1); 
      quickSort(a, q+1, r); 
     } 
    } 

    private static int Partition(int[] a, int p, int r) 
    { 
     int x = a[r]; 

     int i = p-1; 
     int temp=0; 

     for(int j=p; j<r; j++) 
     { 
      if(a[j]<=x) 
      { 
       i++; 
       temp = a[i]; 
       a[i] = a[j]; 
       a[j] = temp; 
      } 
     } 
     temp = a[i+1]; 
     a[i+1] = a[r]; 
     a[r] = temp; 
     return (i+1); 
    } 
} 

Answer 1

所以，如果我理解正確的話，你可以進行排序int秒的快速排序法現在您的要求是排序City對象。我想你可以在互聯網上找到很多靈感。首先你需要指定一個排序順序。既然你想不同的排序順序（按人口，按字母順序等），寫一個Comparator<City>是這樣做的。搜索你的教科書和/或網絡的指導和例子。你的比較器需要你的City類來獲取方法，所以也要添加一些。例如，比較受人口（最大第一）排序可能是

Comparator<City> populationComparator = Comparator.comparingInt(City::getPopulation).reversed(); 

這將要求City有getPopulation方法。

接下來你需要重寫你的quicksort方法來接受一個City對象和一個比較器的數組，而Partition()也是一樣的。裏面的Partition方法，它說：a[j]<=x，由cityComparator.compare(a[j], x) <= 0取代（如果你的比較參數被稱爲cityComparator）。您需要更改x和其他變量保持要素City的類型。