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我不知道如何通過多處理工作來計算壞像素我到目前爲止沒有多處理並分析需要分析的10張圖片大約需要7分鐘...通過在Python中使用多處理來計算死像素
import random
import time
from multiprocessing import Process, Queue, current_process, freeze_support
from PIL import Image, ImageDraw
image1 = Image.open('MA_HA1_drawing_0.png')
image2 = Image.open('MA_HA1_drawing_1.png')
image2 = Image.open('MA_HA1_drawing_2.png')
image3 = Image.open('MA_HA1_drawing_3.png')
image4 = Image.open('MA_HA1_drawing_4.png')
image5 = Image.open('MA_HA1_drawing_5.png')
image6 = Image.open('MA_HA1_drawing_6.png')
image7 = Image.open('MA_HA1_drawing_7.png')
image8 = Image.open('MA_HA1_drawing_8.png')
image9 = Image.open('MA_HA1_drawing_9.png')
def analyze_picture(image):
time.sleep(0.5*random.random())
counter = 0
for x in range(616,6446):
for y in range(756,3712):
r,g,b = image.getpixel((x,y))
if r != 1 and g != 1 and b != 1:
counter += 1
return counter
def test():
NUMBER_OF_PROCESSES = 4
TASKS1 = [(analyze_picture(image1))]
TASKS2 = [(analyze_picture(image2))]
TASKS3 = [(analyze_picture(image2))]
TASKS4 = [(analyze_picture(image3))]
TASKS5 = [(analyze_picture(image4))]
TASKS6 = [(analyze_picture(image5))]
TASKS7 = [(analyze_picture(image6))]
TASKS8 = [(analyze_picture(image7))]
TASKS9 = [(analyze_picture(image8))]
TASKS10 = [(analyze_picture(image9))]
print TASKS1
if __name__ == '__main__':
freeze_support()
test()
他們給了我們一些功能來理解多處理並將其用於我們的任務,但我不理解他們,也不知道如何使用它們。
def worker(input, output):
for func, args in iter(input.get, 'STOP'):
result = calculate(func, args)
output.put(result)
def calculate(func, args):
result = func(*args)
return '%s says that %s%s = %s' % \
(current_process().name, func.__name__, args, result)
def mul(a, b):
time.sleep(0.5*random.random())
return a * b
def plus(a, b):
time.sleep(0.5*random.random())
return a + b
# Create queues
task_queue = Queue()
done_queue = Queue()
# Submit tasks
for task in TASKS1:
task_queue.put(task)
# Start worker processes
for i in range(NUMBER_OF_PROCESSES):
Process(target=worker, args=(task_queue, done_queue)).start()
print i
# Get and print results
print 'Unordered results:'
for i in range(len(TASKS1)):
print '\t', done_queue.get()
# Add more tasks using `put()`
for task in TASKS2:
task_queue.put(task)
# Get and print some more results
for i in range(len(TASKS2)):
print '\t', done_queue.get()
# Tell child processes to stop
for i in range(NUMBER_OF_PROCESSES):
task_queue.put('STOP')
print 'process ', i, ' is stopped'
編輯:新代碼
import random
import time
from multiprocessing import Process, Queue, current_process, freeze_support
from PIL import Image, ImageDraw
def worker(input, output):
for func, args in iter(input.get, 'STOP'):
result = calculate(func, args)
output.put(result)
def calculate(func, args):
result = func(args)
return '%s says that %s%s has %s dead pixels\n' % \
(current_process().name, func.__name__, args, result)
def analyze_picture(image_name):
t1 = time.clock()
image = Image.open(image_name)
time.sleep(0.5*random.random())
counter = 0
for x in range(616,6446):
for y in range(756,3712):
r,g,b = image.getpixel((x,y))
if r != 1 and g != 1 and b != 1:
counter += 1
t2 = time.clock()
dt = t2 - t1
print '\tThe process takes ',dt,' seconds.\n Result:\n'
return counter
def test():
NUMBER_OF_PROCESSES = 4
TASKS1 = [(analyze_picture, image_names[i]) for i in range(10)]
print TASKS1
# Create queues
task_queue = Queue()
done_queue = Queue()
# Submit tasks
for task in TASKS1:
task_queue.put(task)
# Start worker processes
for i in range(NUMBER_OF_PROCESSES):
Process(target=worker, args=(task_queue, done_queue)).start()
print i
# Get and print results
print 'Unordered results:'
for i in range(len(TASKS1)):
print '\t', done_queue.get()
# Tell child processes to stop
for i in range(NUMBER_OF_PROCESSES):
task_queue.put('STOP')
print 'process ', i, ' is stopped'
if __name__ == '__main__':
image_names =[('MA_HA1_drawing_'+str(i)+'.png') for i in range(10)]
freeze_support()
test()
嗨@Chickenmarkus非常感謝你的詳細答覆。我很感激它,我試過它,然後你給我的答案,我得到它的工作,但現在我有另一個問題,結果是這樣的https://pastebin.com/gsviTkLj ,但我想它像 該過程需要x秒 結果 圖像X滿足x壞點 而不是 過程耗時x秒 結果 這個過程需要x秒...... 我將編輯我的問題,用新的代碼,所以你能看到,也許是問題 –
的在'analyze_picture()'中打印時間,'test()'中結果的打印是由於多處理而異步運行的。工人通常不應該印刷一些東西(因爲不確定的不同步,而且通常有很多工人)。讓worker只返回值(或字符串),而只在主進程test()中打印它。 – Chickenmarkus