我正在嘗試構建論壇。我有一個包含一行標題,一行編輯鏈接和一行刪除鏈接的表。當我點擊編輯鏈接時,我被帶到edit.php,在那裏我有另一種形式插入新的主題標題。當我點擊「保存新主題」按鈕時,該行應該更新,但這是我的問題,標題保持不變。我一直在尋找這個網站(和一般的網絡)尋找解決方案,但沒有人似乎爲我工作。在php中編輯行
在forum.php我有這樣的代碼:
<?php
while ($row = mysqli_fetch_assoc($result))
{
$subject = $row['subject'];
$id = $row['id'];
?>
<tr>
<th><a href="viewtopic.php?id=<?php echo $row ['id']?> "> <?php echo $row ['subject']?> </a></th>
<th><a href="edit.php?id=<?php echo $row['id']?> ">Edit</a></th>
<th><a href="delete.php?id=<?php echo $row['id']?> ">Delete</a></th>
</tr>
<?php
}
?>
在edit.php我有這樣的代碼:
<div id="form">
<form id='edit' action='edit.php' method='post' >
<fieldset>
<legend>Edit Topic</legend>
<br />
<label for='name' >New Subject</label><br/>
<input type="text" id="subject" name="newsubject" /><br />
<br/>
<input type='hidden' name='id' value='<?php echo $id ?>'/>
<input type="submit" name="save" value="Save New Topic" />
</fieldset>
</form>
</div>
<?php
if (isset($_POST['save']))
{
$subject_save = $_POST['newsubject'];
require_once("db_connection.php");
$conn = connectToMySQL();
$id =$_POST['id'];
$query = "UPDATE tbl_topic SET subject = '$subject_save' WHERE id = 'id'";
$result = mysqli_query($conn, $query)
or die("Error in query: ".mysqli_error($conn));
header("Location: forum.php");
die();
}
?>
「我點擊‘保存新主題’按鈕,該行應該被更新」 - 這行應在forum.php或edit.php更新? –