Python 3 - ValueError：沒有足夠的值來解壓縮（預計3，得到2）

Question

我的Python 3程序有問題。我使用Mac OS X.此代碼運行正常。

# -*- coding: utf-8 -*- 
#! python3 
# sendDuesReminders.py - Sends emails based on payment status in spreadsheet. 

import openpyxl, smtplib, sys 


# Open the spreadsheet and get the latest dues status. 
wb = openpyxl.load_workbook('duesRecords.xlsx') 
sheet = wb.get_sheet_by_name('Sheet1') 

lastCol = sheet.max_column 
latestMonth = sheet.cell(row=1, column=lastCol).value 

# Check each member's payment status. 
unpaidMembers = {} 
for r in range(2, sheet.max_row + 1): 
payment = sheet.cell(row=r, column=lastCol).value 
if payment != 'zaplacone': 
    name = sheet.cell(row=r, column=2).value 
    lastname = sheet.cell(row=r, column=3).value 
    email = sheet.cell(row=r, column=4).value 
    unpaidMembers[name] = email 


# Log in to email account. 
smtpObj = smtplib.SMTP_SSL('smtp.gmail.com', 465) 
smtpObj.ehlo() 
smtpObj.login('abc@abc.com', '1234') 


# Send out reminder emails. 
for name, email in unpaidMembers.items() 
body = "Subject: %s - przypomnienie o platnosci raty za treningi GIT Parkour. " \ 
     "\n\nPrzypominamy o uregulowaniu wplaty za uczestnictwo: %s w treningach GIT Parkour w ." \ 
     "\n\nRecords show that you have not paid dues for %s. Please make " \ 
     "this payment as soon as possible."%(latestMonth, name, latestMonth) 
print('Sending email to %s...' % email) 
sendmailStatus = smtpObj.sendmail('abc@abc.com', email, body) 

if sendmailStatus != {}: 
    print('There was a problem sending email to %s: %s' % (email, 
    sendmailStatus)) 
smtpObj.quit()enter code here 

當我試圖向for循環添加下一個值時，問題就開始了。

# Send out reminder emails. 
for name, lastname, email in unpaidMembers.items() 
body = "Subject: %s - przypomnienie o platnosci raty za treningi GIT Parkour. " \ 
     "\n\nPrzypominamy o uregulowaniu wplaty za uczestnictwo: %s %s w treningach GIT Parkour w ." \ 
     "\n\nRecords show that you have not paid dues for %s. Please make " \ 
     "this payment as soon as possible."%(latestMonth, name, lastname, latestMonth) 
print('Sending email to %s...' % email) 
sendmailStatus = smtpObj.sendmail('abc@abc.com', email, body) 

終端顯示錯誤：

Traceback (most recent call last): 
    File "sendDuesEmailReminder.py", line 44, in <module> 
     for name, email, lastname in unpaidMembers.items(): 
ValueError: not enough values to unpack (expected 3, got 2) 

Answer 1

你可能想分配lastname你在這裏

lastname = sheet.cell(row=r, column=3).value 

讀出的東西;目前該方案只是忘記它

你能做到這兩條線後，像這樣

unpaidMembers[name] = lastname, email 

你的程序仍然會崩潰，在同一個地方，因爲.items()仍然不會給你3元組，而是一些有這種結構：(name, (lastname, email))

好消息是，蟒蛇可以處理這個

for name, (lastname, email) in unpaidMembers.items(): 

等等

Answer 2

在這一行：

for name, email, lastname in unpaidMembers.items(): 

unpaidMembers.items()必須每次迭代只有兩個值。

這裏是一個小例子來說明這個問題：

這將工作：

for alpha, beta, delta in [("first", "second", "third")]: 
    print("alpha:", alpha, "beta:", beta, "delta:", delta) 

這會失敗，是你的代碼做什麼：

for alpha, beta, delta in [("first", "second")]: 
    print("alpha:", alpha, "beta:", beta, "delta:", delta) 

在這最後例如，列表中的值分配給delta？沒有，沒有足夠的價值觀，那就是問題所在。

Answer 3

由於unpaidMembers是字典當使用.items()（鍵值）調用時，它始終返回兩個值。您可能希望將數據保存爲元組列表[(name, email, lastname), (name, email, lastname)..]。