當我運行這部分代碼時,它給了我一個SQLException。所有的MySQL信息都是正確的,我使用的代碼完全在不同的類中,但只是查詢其他的東西,它工作得很好。SQLException結果集結束後
這裏是堆棧跟蹤
[23:24:06 WARN]: java.sql.SQLException: After end of result set
[23:24:06 WARN]: at com.mysql.jdbc.SQLError.createSQLException(SQLError.java:963)
[23:24:06 WARN]: at com.mysql.jdbc.SQLError.createSQLException(SQLError.java:896)
[23:24:06 WARN]: at com.mysql.jdbc.SQLError.createSQLException(SQLError.java:885)
[23:24:06 WARN]: at com.mysql.jdbc.SQLError.createSQLException(SQLError.java:860)
[23:24:06 WARN]: at com.mysql.jdbc.ResultSetImpl.checkRowPos(ResultSetImpl.java:790)
[23:24:06 WARN]: at com.mysql.jdbc.ResultSetImpl.getInt(ResultSetImpl.java:2472)
[23:24:06 WARN]: at com.mysql.jdbc.ResultSetImpl.getInt(ResultSetImpl.java:2583)
[23:24:06 WARN]: at me.Austin.MT.RecentTickets.recentTickets(RecentTickets.java:47)
[23:24:06 WARN]: at me.Austin.MT.GUIs.AdminGUIManager.onInvClick(AdminGUIManager.java:94)
[23:24:06 WARN]: at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method)
[23:24:06 WARN]: at sun.reflect.NativeMethodAccessorImpl.invoke(Unknown Source)
[23:24:06 WARN]: at sun.reflect.DelegatingMethodAccessorImpl.invoke(Unknown Source)
[23:24:06 WARN]: at java.lang.reflect.Method.invoke(Unknown Source)
[23:24:06 WARN]: at org.bukkit.plugin.java.JavaPluginLoader$1.execute(JavaPluginLoader.java:302)
[23:24:06 WARN]: at org.bukkit.plugin.RegisteredListener.callEvent(RegisteredListener.java:62)
[23:24:06 WARN]: at org.bukkit.plugin.SimplePluginManager.fireEvent(SimplePluginManager.java:502)
[23:24:06 WARN]: at org.bukkit.plugin.SimplePluginManager.callEvent(SimplePluginManager.java:487)
[23:24:06 WARN]: at net.minecraft.server.v1_11_R1.PlayerConnection.a(PlayerConnection.java:1844)
[23:24:06 WARN]: at net.minecraft.server.v1_11_R1.PacketPlayInWindowClick.a(SourceFile:33)
[23:24:06 WARN]: at net.minecraft.server.v1_11_R1.PacketPlayInWindowClick.a(SourceFile:10)
[23:24:06 WARN]: at net.minecraft.server.v1_11_R1.PlayerConnectionUtils$1.run(SourceFile:13)
[23:24:06 WARN]: at java.util.concurrent.Executors$RunnableAdapter.call(Unknown Source)
[23:24:06 WARN]: at java.util.concurrent.FutureTask.run(Unknown Source)
[23:24:06 WARN]: at net.minecraft.server.v1_11_R1.SystemUtils.a(SourceFile:46)
[23:24:06 WARN]: at net.minecraft.server.v1_11_R1.MinecraftServer.D(MinecraftServer.java:739)
[23:24:06 WARN]: at net.minecraft.server.v1_11_R1.DedicatedServer.D(DedicatedServer.java:399)
[23:24:06 WARN]: at net.minecraft.server.v1_11_R1.MinecraftServer.C(MinecraftServer.java:675)
[23:24:06 WARN]: at net.minecraft.server.v1_11_R1.MinecraftServer.run(MinecraftServer.java:574)
[23:24:06 WARN]: at java.lang.Thread.run(Unknown Source)
下面是代碼
public class RecentTickets {
public static HashMap<Integer, String> rTickets = new HashMap<>();
/*
* TODO: Return the most 5 recent
*
*
*/
/**
* RecentTickers Class - Returns the recent tickets
*
* @param p Player that runs the command
* @return The 5 most recent tickets
* @throws SQLException Just in case MySQL wants to be a dick
*/
public static HashMap<Integer, String> recentTickets(Player p) throws SQLException {
rTickets.clear();
int t = 0;
Statement statement = MySQL.getConnection().createStatement();
ResultSet r2 = statement
.executeQuery("SELECT COUNT(*) FROM tickets ORDER BY Date DESC;");
while (r2.next()) {
t = r2.getInt(1);
}
if (t > 5) {
ResultSet result = statement.executeQuery("SELECT * FROM tickets ORDER BY Date DESC LIMIT 5;");
result.next();
int i;
for (i = 0; i < t; i++) {
rTickets.put(result.getInt("TicketID"), result.getString("UUID"));
result.next();
}
return rTickets;
} else {
ResultSet result = statement.executeQuery(
"SELECT * FROM tickets ORDER BY Date DESC LIMIT " + t + ";");
result.next();
int i;
for (i = 0; i < t; i++) {
rTickets.put(result.getInt("TicketID"), result.getString("UUID"));
result.next();
}
return rTickets;
}
}
}
最後一次調用不起作用,因爲result.hasNext()不存在。 –
哦對!我認爲它會有一個hasNext方法,但它應該和第一個while循環一樣。更新了答案 –
出於好奇,還有一件事是,你爲什麼首先計數,然後根據計數設置限制?我的意思是如果你直接運行SELECT * FROM票據ORDER BY Date DESC LIMIT 5;這隻有5個以上時才能得到5個,如果少於5個,你會得到那麼多。這看起來對我來說太過分了。如果有2行,並且你放了限制5,你仍然只能得到2行。 –