2016-05-30 94 views
4

我需要通過JSON格式的組件來獲得漏洞獲取漏洞,但我已經用CVE Details API只是單一的弱點得到其中任何組件或東西,只描述。CVE詳細API,通過組件

這裏是鏈接的例子

http://www.cvedetails.com/json-feed.php?numrows=10&vendor_id=0&product_id=0&version_id=0&hasexp=0&opec=0&opov=0&opcsrf=0&opfileinc=0&opgpriv=0&opsqli=0&opxss=0&opdirt=0&opmemc=0&ophttprs=0&opbyp=0&opginf=0&opdos=0&orderby=3&cvssscoremin=0 

這裏是JSON的一個例子:

{ 
    "cve_id": "CVE-2016-4951", 
    "cwe_id": "0", 
    "summary": "The tipc_nl_publ_dump function in net/tipc/socket.c in the Linux kernel through 4.6 does not verify socket existence, which allows local users to cause a denial of service (NULL pointer dereference and system crash) or possibly have unspecified other impact via a dumpit operation.", 
    "cvss_score": "7.2", 
    "exploit_count": "0", 
    "publish_date": "2016-05-23", 
    "update_date": "2016-05-24", 
    "url": "http://www.cvedetails.com/cve/CVE-2016-4951/" 
} 

是否有任何方式的組件的名稱來獲得漏洞? (新老)

回答