在PHP

Question

什麼是我想要得到的是對array_key_exists（）的每次迭代返回true ..

我不知道check_mobile_exists( $mobiles, $electronics)這個函數返回true的時間。我想在$ electronics key列表中存在$ mobile數組鍵時爲true，當不存在時爲false。在這個結果的基礎上，我正在循環發佈結果。但正如我所說的那樣，函數在每次迭代中都會返回true。任何人建議我現在應該做什麼？

function check_mobile_exists( $mobiles, $electronics) { 
    foreach($mobiles as $mobile => $price) { 
     if(array_key_exists($mobile, $electronics)) { 
      return true; 
     } 
     return false; 
    } 
} 

$mobiles = array(
    'iPhone' => '$350', 
    'tablet' => '$100', 
    'samsung' => '$200', 
    'walton' => '$60' 
); 

$electronics = array(
    'iPhone' => 'OK', 
    'tablet' => 'will do', 
    'walton' => 'No need' 
); 

while(have_posts()): the_post(); 
    if(check_mobile_exists( $mobiles, $electronics)){ // returning only true on every iterating 
     echo get_the_title() .' do something....<br />'; 
    } else { 
     echo 'Do another....'; 
    } 
endwhile; 

Answer 1

試試這個

$mobiles = array(
    'iPhone' => '$350', 
    'tablet' => '$100', 
    'samsung' => '$200', 
    'walton' => '$60' 
); 
$electronics = array(
    'iPhone' => 'OK', 
    'tablet' => 'will do', 
    'walton' => 'No need' 
); 

while(have_posts()): the_post(); 
    foreach($mobiles as $mobile => $price) { 
    if(array_key_exists($mobile, $electronics)) { 
     echo get_the_title() .' do something....<br />'; 
    }else{ 
     echo 'Do another....'; 
    } 
    } 
endwhile; 

更新：所以你說，沒有使用其他的功能，你可以做到這一點。

Answer 2

做它不用其他檢查移動功能

$mobiles = array(
    'iPhone' => '$350', 
    'tablet' => '$100', 
    'samsung' => '$200', 
    'walton' => '$60' 
); 
$electronics = array(
    'iPhone' => 'OK', 
    'tablet' => 'will do', 
    'walton' => 'No need' 
); 




while(have_posts()): the_post(); 
    foreach ($mobiles as $m_key => $mobile) { 
    if (array_key_exists($m_mey, $electronics)) { 
     do somethin 
    } else { 
     do somethin 
    } 
} 
endwhile;