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我想從我的數據庫檢索數據使用和HTML表單和PHP連接到我的sql-workbench。我有一個成功的數據庫連接,我的檢索發佈在我的網頁頂部。我不知道如何讓它在提交表單函數上運行sql查詢。 任何幫助,將不勝感激,謝謝。使用HTML表單來搜索和從mysql工作臺檢索數據由php
<!DOCTYPE html>
<html>
<head data-gwd-animation-mode="quickMode">
<title>Test_webpage</title>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8">
<meta name="generator" content="Google Web Designer 1.1.3.1119">
</head>
<body>
<?php
$servername = "localhost";
$username = "root";
$password = "006";
$dbname = "mydb";
// Create connection
$con = new mysqli($servername, $username, $password, $dbname);
//$con->close();
//$query = "SELECT * FROM US_Cars";
if ($con->connect_error) {
die("Connection failed: " . $con->connect_error);
}
$sql = "SELECT Manufacturer,VIN,Color,Model,Fuel_Type,State_of_Origin FROM mydb.US_Cars;";
$result = $con->query($sql);
if ($result->num_rows > 0) {
// output data of each row
while($row = $result->fetch_assoc()) {
echo "Manufacturer: " . $row["Manufacturer"]. " VIN: " . $row["VIN"]. " Color:" . $row["Color"]. " Model:" . $row["Model"]. " Fuel Type:" . $row["Fuel_Type"]. " State Location:" . $row["State_of_Origin"]. "<br>";
}
} else {
echo "0 results";
}
?>
<div id="first">
<p>Enter Criteria Below to Search.</p>
</div>
<br>
<div id="second">
<p class="gwd-p-j2b6">Select a Manufacturer</p>
<!-- start of form -->
<form class="gwd-form-yuwo" method="post" action="<?search2.php ?>">
<select class="auto-style3 gwd-select-u9g0">
<option value="GM">GM</option>
<option value="Ford">Ford</option>
<option value="Chrysler">Chrysler</option>
<option value="Tesla">Tesla</option>
</select>appreaciated
<br>
<br>
<p class="gwd-p-cy97">Select a Dealership Location</p>
<select class="auto-style3 gwd-select-dkho">
<option value="">Virginia</option>
<option value="">Maryland</option>
<option value="">New Jesery</option>
<option value="">Kentucky</option>
</select>
<br>
<input type="submit" value="Submit" class="auto-style2">
</form>
</div>
<div id="third">
<img id="pic1" src="page2_1.jpg" style="width:500px;" height="236px" >
</div>
<div id="forth">
<img src="tesla.png" style="width:125px;height:250px">
</div>
<div id="fifth">
<footer>
<p>
<a href="">U.S. Car data Entry</a>
</p>
<p>
<a href="">About Page</a>
</p>
</footer>
</div>
</body>
</html>
首先,'action =「<?search2.php?>」'這是值得懷疑的。如果沒有設置短標籤,這個'action =「<?php search2.php?>」'可以被修改。如果你想從數據庫中檢索,你需要分配POST變量並命名你的表單元素。 – 2014-12-03 02:39:04