PHP web表單不顯示用戶的電子郵件輸入從字段

我的網頁表單以其他任何方式工作，除非我收到來自網絡表單的提交，它表示發件人是Apache，當我希望它說出用戶的名稱或網站的名稱時，表單已經提交。這裏是我的代碼：

<?php 

if(empty($_POST['submit'])) 
{ 
echo "Form is not submitted!"; 
exit; 
} 
if(empty($_POST["name"]) || 
empty($_POST["email"])) 
{ 
    echo "Please complete required fields"; 
    exit; 
} 
if(isset($_POST['submit'])){ 
$to = "[email protected]"; 

$from = $_POST['email']; 
$name = $_POST['name']; 
$phone = $_POST['phone']; 
$subject = "Form Submission"; 
$subject2 = "Copy of Your Form Submission"; 
$message = $_POST['comment'] . "\n " . "From:" . " " . $_POST['name'] . 
"\n " . "Telephone:" . " " . $_POST['phone'] . "\n " . :Email:" . " " . $_POST 

['email']; 
$message2 = "Thank you for your enquiry." . "\n " . 

"Here is a copy of your enquiry for your records: " . "\n " . $_POST['comment'] 
. "\n " . "A member of our team will contact you shortly to discuss your 

requirements."; 






$headers = "From:" . $from; 
$headers2 = "From:" . $to; 


mail($to, $subject, $headers, $message); 
mail($from, $subject2, $message2, $headers2); 
} 



header('Location: thank-you.html'); 


?>

我試圖從變量改說別的，然後就張貼該使用者的消息中的電子郵件地址，這樣我至少可以獲取信息的方式。這有點破了！任何幫助將是非常讚賞:)

來源

2014-09-29 ncrbrts

發佈您的HTML以及。 – Rimble 2014-09-29 13:12:03

您好，我無法評論所以在回答部分寫着：

if(empty($_POST['submit'])) 
{ 
echo "Form is not submitted!"; 
exit;

這是什麼的？

來源

2014-09-29 12:42:50

PHP web表單不顯示用戶的電子郵件輸入從字段

回答

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