用於輸出HTML電子郵件的聯繫表單 - 未輸入電子郵件中的數據

我一直在處理聯繫表單，該表單將輸出到將通過電子郵件發送到地址的html電子郵件。這個過程非常漂亮，但它不會將數據放入html電子郵件中供收件人閱讀。用於輸出HTML電子郵件的聯繫表單 - 未輸入電子郵件中的數據

<?php 
    if(isset($_POST['submit'])) { 

    //create an empty errors array 
    $errors = array(); 
    //our form has been submitted 
    if($_POST['name'] == "") { 
    //the name field is empty 
    $errors[] = "The Name field is empty."; 
    } 
    if($_POST['business'] == "") { 
    //the business field is empty 
    $errors[] = "The Business name field is empty."; 
    } 
    if($_POST['telephone'] == "") { 
    //the telephone number field is empty 
    $errors[] = "The Telephone Number field is empty."; 
    } 
    if($_POST['email'] == "") { 
    //the email field is empty 
    $errors[] = "The Email address field is empty."; 
    } 
    if($_POST['enquiry'] == "") { 
    //the enquiry field is empty 
    $errors[] = "The Enquiry field is empty."; 
    } 
    if(!stripos($_POST['email'], '@')) { 
     $errors[] = "The email address was not valid."; 
    } 
    if($_POST['antispam'] != 10) { 
     $errors[] = "You entered the wrong numerical answer for the anti-spam question."; 
    } 
    if(count($errors) == 0) { 

    // email settings 
    $to = '[email protected]' . ', '; 
    $subject = 'Website Enquiry Form'; 

    // headers 
    $headers = 'MIME-Version: 1.0' . "\r\n"; 
    $headers .= 'Content-type: text/html; charset=iso-8859-1' . "\r\n"; 
    $headers .= 'Return-Path: [email protected]' . "\r\n"; 

    // form details 
    $name = $_POST['name']; 
    $business = $_POST['business']; 
    $telephone = $_POST['telephone']; 
      $email = $_POST['email']; 
      $type = $_POST['type']; 
      $enquiry = $_POST['enquiry']; 

    $message = ' 
    <html> 
    <head> 
    <title>Website Enquiry Form</title> 
    </head> 
    <body>    
    The details from completed enquiry form on the website is: <br><br> <strong> $name </strong>from <strong> $business </strong> has filled the form out. The contact details for<strong> $name </strong> is<strong> $telephone </strong> and<strong> $email </strong> is the listed email address.<br><br> <strong> $type </strong> is the selected type of enquiry.<br><br> <strong>Comments:</strong><br> $enquiry <br><br>This is the end of the enquiry form. 
    </body> 
    </html> 
    '; 

     if(mail($to, $subject, $message, $headers)) { 
      $success = true; 
     } else { 
      $success = false; 
     } 
     } else { 
      $success = false; 
     } 
    } 
?>

這是聯繫查詢表格的PHP。這是一個現有的，我以前有一個修改，但沒有HTML輸出，並在代碼「的消息：」以前是：

<<<DATA 
<strong>Name:</strong> $name <br> 
<strong>Email:</strong> $email <br> 
<strong>Why:</strong> $subject <br> 
<strong>Comment:</strong> $comments<br> 
DATA;

，然後工作，但我試圖把<<<DATA和結尾在HTML代碼之前的DATA;，然後它不起作用。我不是一個真正的開發者，所以我不知道從哪裏開始。我希望有人能夠指出我對此的正確方向。

來源

2012-03-22 j_mes

設置您的$message變量時，您使用單引號（'）來分隔字符串。這導致php在而不是解析字符串中的變量。您可以使用雙引號（「）來代替：

$message = "<html><body>Name: $name</body></html>";

或連接字符串，像這樣：

$message = '<html><body>Name: '.$name.'</body></html>';

來源

2012-03-22 11:33:33

對$ message變量使用雙引號，如$message = "<html>...</html>"。

來源

2012-03-22 11:28:08 slash197

您需要在$ message中使用雙引號。

來源

2012-03-22 11:28:31

用於輸出HTML電子郵件的聯繫表單 - 未輸入電子郵件中的數據

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