Python的 - 比較鍵

Question

值說出我們有以下兩個字典中Python：

dict1 = {'a':1, 'b':2, 'c':3, 'd': 4} 

dict2 = {'c':2, 'd':1, 'b':2, 'a':1} 

現在，我假設在dict1值是正確的值。我如何將dict2與dict1進行比較，如果dict2中的密鑰值與dict1中的密鑰值相似，程序將返回True，如果不同，則返回False？

謝謝。

Answer 1

如果類似你的意思是相等的，那麼你可以直接對它們進行比較：

def compare_dictionaries(correct_dictionary,dictionary_to_check): 
    for key,correct_value in correct_dictionary.items(): 
     if dictionary_to_check[key] != correct_value: 
      return False 
    return True 

以上會，如果你缺少你需要檢查辭典的鍵，拋出一個KeyError異常，並沒有採取任何措施如果你正在檢查的字典包含額外的密鑰，則處理。

Answer 2

先執行

# Both dictionaries can have different keys 

dict1 = {'a':1, 'b':2, 'c':3, 'd': 4} # correct dict 
dict2 = {'c':2, 'd':1, 'b':2, 'a':1} # test dict 
if all(map(lambda x: dict2.get(x, "dict2") == dict1.get(x, "dict1"), dict2)): 
    print "same" 
else: 
    print "different" 

測試用例＃1給出 「相同」

dict1 = {'a':1, 'b':2, 'c':3, 'd': 4, 'e':5} # correct dict 
dict2 = {'c':3, 'd':4, 'b':2, 'a':1} # test dict 

試驗例＃2給出 「不同」

dict1 = {'a':1, 'b':2, 'c':3, 'd': 4 } # correct dict 
dict2 = {'c':3, 'd':4, 'b':2, 'a':1, 'e':5} # test dict 

第二實現（從第一不同，看測試結果）

# Both dictionaries can have different keys 

dict1 = {'a':1, 'b':2, 'c':3, 'd': 4} # correct dict 
dict2 = {'c':2, 'd':1, 'b':2, 'a':1} # test dict 
if set(dict1.keys()) == set(dict2.keys()) and set(dict1.values()) == set(dict2.values()): 
    print "same" 
else: 
    print "different" 

測試案例＃1給出了 「不同」

dict1 = {'a':1, 'b':2, 'c':3, 'd': 4, 'e':5} # correct dict 
dict2 = {'c':3, 'd':4, 'b':2, 'a':1} # test dict 

測試案例＃2給出了 「不同」

dict1 = {'a':1, 'b':2, 'c':3, 'd': 4 } # correct dict 
dict2 = {'c':3, 'd':4, 'b':2, 'a':1, 'e':5} # test dict 

Answer 3

我猜測dict1鍵：值是什麼一切都被比較。

dict2 = {'c':2, 'd':1, 'b':2, 'a':1} 

def compareDict(d2): 
    dict1 = {'a':1, 'b':2, 'c':3, 'd': 4} 

    for key in d2: 
    if d2[key] == dict1[key]: 
     print("{} key has similar value of {}; It is True".format(key, 
     d2[key])) 
    else: 
     print("{} key does not have similar value as dict1 key, it has a 
     value of {}; It is False".format(key, d2[key])) 

compareDict(dict2) 

Answer 4

首先檢查密鑰是相同的使用xor操作，然後與對應的dictionary的key檢查值。希望這會有所幫助。

dict1 = {'a':2, 'b':2, 'c':3, 'd': 4} 
dict2 = {'c':2, 'd':1, 'b':2, 'a':1} 
# XOR operator for for checking all key are same. 
check_keys= set(dict1.keys())^set(dict2.keys()) 
keys = set(dict2.keys()) 
check = False 
# a=0 if all key are same. 
a = len(check_keys) 
# if all key are same than check the value with corresponding key 
if not a: 
    check = True 
    for key in keys: 
     if dict1[key] == dict2[key]: 
      pass 
     else: 
      check = False 
      break 
print(check) 

Answer 5

通過給出布爾標誌來比較字典的大小，鍵和值。

def compareDictionaries(source, target, compareValues): 
    ## compare if they are same 
    if (source == target): 
     return True 
    ## covers scenario where target has more keys than source 
    if (len(target) > len(source)): 
     print("target has more keys than source") 
     return False 
    ## iterate over target keys to check if they exists in 
    ## source and depending on compareValues flag compare key's 
    ## values 
    for key, values in target.items(): 
     if (key in source.keys()): 
      if (compareValues): 
       if(not (source[key] == target[key])): 
        print ("key(" + key + ") don't have same values!") 
        return False 
     else: 
      print ("key(" + key + ") not found in source!") 
      return False 
    return True 

dict1 = {'a':1, 'b':2, 'c':3, 'd': 4} 
dict2 = {'c':5, 'd':4, 'b':2, 'a':1} 
if (compareDictionaries(dict1, dict2, False)): 
    print("Pass") 
else: 
    print("Fail")