未能找到類 - Spring 3，Hibernate 3，JPA

看來我的類沒有被JPA的基礎結構找到。我猜春天不能找到它？我已經試過包掃描並將類添加到persistence.xml。那裏的任何人都有什麼想法可以嘗試讓我的選擇找到該類（和基礎表）？謝謝！未能找到類 - Spring 3，Hibernate 3，JPA

這是代碼。

的persistence.xml

<persistence-unit name="myApp" transaction-type="RESOURCE_LOCAL"> 
    <provider>org.hibernate.ejb.HibernatePersistence</provider> 
    <jta-data-source>java:joss/datasources/myDB</jta-data-source> 
    <!-- get a special error with this in - see below --> 
    <!-- <class>com.src.dao.User</class> --> 

    <exclude-unlisted-classes>false</exclude-unlisted-classes> 
    <properties> 
    <property name="hibernate.archive.autodetection" value="class,hbm" />

UserDAO的代碼導致錯誤：時拋出

final String queryString="select model from " +User.class.getSimpleName() + " model where model."propertyName+"=:propertyValue"; 
return getJpaTemplate().executeFind(new JpaCallback() { 
    @Override 
    public Object doInJpa(EntityManager em) throws PersistenceException { 
     //this line causes the error below 
     Query query = em.createQuery(queryString);

錯誤：

201-06-10 18:59:32,736 ERROR [UserDAO] find by property name failed 
org.springframework.dao.InvalidDataAccessApiUsageException: org.hibernate.hql.internal.ast.QuerySyntaxException: User is not mapped [select model from User model where model.value= :propertyValue]; nested exception is java.lang.IllegalArgumentException: org.hibernate.hql.internal.ast.QuerySyntaxException:User is not mapped [select model from User model where model.value= :propertyValue] 
    at org.springframework.orm.jpa.EntityManagerFactoryUtils.convertJpaAccessExceptionIfPossible(EntityManagerFactoryUtils.java:286)

的applicationContext.xml

<context:annotation-config /> 
<context:component-scan base-package="com.src.dao" />

也嘗試過一個bean中

<beans:bean id="entityManagerFactory" class="org.springframework.orm.jpa.LocalEntityManagerFactoryBean" packagesToScan="com.src.dao"> 
    <beans:property name="persistenceUnitName" value="myApp" /> 
    <beans:property name="packagesToScan" value="com.src.dao" /> 
</beans:bean>

用戶類別：

package com.src.dao 

import javax.persistence.Entity; 
import javax.persistence.Table; 
import javax.persistence.Transient; 

/** 
* User Entity 
* 
* @author MyEclipse Persistence Tools 
*/ 
@Entity 
@Table (name="USERS", schema="myDb") 
public class User extends AbstractUser implements java.io.Serializable, Comparable<User> {

添加類persistence.xml中：

When I add in <class> to my persistence.xml I get the following on app deploy. The war never deploys: 

Error creating bean with name 'entityManagerFactory' defined in ServletContext resource [/WEB-INF/configs/spring/stu-hibernate.xml]: Invocation of init method failed; nested exception is javax.persistence.PersistenceException: [PersistenceUnit: myApp] Unable to build EntityManagerFactory 
    at org.springframework.beans.factory.annotation.AutoWiredAnnotationBeanPostProcessor.postProcessPropertyValues(AutowiredAnnotationBeanPostProcessor.java:285)

來源

2016-06-10 Blake

發佈堆棧跟蹤。 –

終於想通了。看來，基於我的Spring版本（3.0.5），我真的需要在persistence.xml中添加該類。但是，我的上述錯誤不會允許。原來......我需要將該包中的所有類添加到persistence.xml（減去DAO）。一旦我做到了，該應用程序啓動並運行！不知道爲什麼他們都需要。

來源

2016-06-13 18:22:58 Blake

未能找到類 - Spring 3，Hibernate 3，JPA

回答

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