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我有一個表值函數,它返回與給定總和相匹配的行集合,它對正值有效,但對負值無效。SQL子集合總和爲負值
有人可以修改這個功能與正反兩方面的價值(價格領域)工作
功能需要一個表的十進制值,然後返回匹配的參數給定的總和的行的第一組合:
例如,如果@psum = 9和給定見下表:
n id price
1 1 4.00
2 2 4.00
3 3 5.00
4 4 6.00
5 5 8.00
的出放是:
select * from SubsetSum2(9)
n id price
3 3 5.00
2 2 4.00
alter FUNCTION [dbo].[SubsetSum2](@psum int)
RETURNS @tt table (n int,id int, price numeric(20,2))
AS
BEGIN
declare @t table (n int IDENTITY(1,1), id int, price numeric(20,2))
insert into @t -- note asc order of book prices
select 1, 4 union all
select 2, 4 union all
select 3, 5 union all
select 4, 6 union all
select 5, 8
declare @rows int, @p numeric(20,2), @sum numeric(20,2) set @sum= 9
delete from @t where price>@sum
set @p=(select sum(price) from @t)
if @p>= @sum
begin --1
set @rows=(select max(n) from @t)
declare @n int, @s numeric(20,2)
set @[email protected]+1 set @s=0
while 0=0
begin --2
while @n>1
begin --3
set @[email protected]
if @s+(select price from @t where [email protected])<[email protected]
and @s+(select sum(price) from @t where n<[email protected])>[email protected]
begin --4
set @[email protected]+(select price from @t where [email protected])
insert into @tt select n, id, price from @t where [email protected]
if @[email protected] return ;
end --4
end --3
set @n=(select min(n) from @tt)
set @[email protected](select price from @tt where [email protected])
delete from @tt where [email protected]
if @s=0 and (select sum(price) from @t where n<@n)<@sum break
end --2
end --1
return
END
請通過告訴我們該功能與應該做什麼來節省時間。以及一些輸出示例。 – Stephen
'-5 + 5 + 5 + 4 = 9'這是不正確的?你希望你的負面金額被視爲積極的? – Stephen
是的,這是正確的,但該功能不適用於該示例。 – oussama