我爲提前:)這個解決方案很抱歉它做你需要什麼,但:
create table TableA(
id int,
string varchar(255)
)
create table table2(
id varchar , text varchar(255)
)
insert into tableA values(1,'a,b,c,d')
insert into tableA values(2,'e,f')
insert into table2 values('a', 'value1')
insert into table2 values('b', 'value2')
insert into table2 values('c', 'value3')
insert into table2 values('d', 'value4')
insert into table2 values('e', 'value5')
insert into table2 values('f', 'value6')
select id, left(myConcat,len(myConcat)-1) from (
select c.id, replace(replace(CAST(CAST('<i'+stuff((select * from(
SELECT A.[id] ,
Split.a.value('.', 'VARCHAR(1000)') AS String
FROM (SELECT [id],
CAST ('<M>' + REPLACE([string], ',', '</M><M>') + '</M>' AS XML) AS String
FROM TableA) AS A CROSS APPLY String.nodes ('/M') AS Split(a)) a
inner join table2 b on a.String = b.id
where a.id = c.id
FOR XML PATH ('')
),1,2,'') AS XML).query('/text') AS VARCHAR(1000)),'<text>',''),'</text>',',') myConcat
from TableA c
group by c.id
) d
請顯示你迄今嘗試過的。 –
我甚至不完全確定從哪裏開始。我正在考慮使用REPLACE函數,但是因爲我不確定如何在每個值的字面意義上寫REPLACE之外如何使用REPLACE函數。 –