檢測2個節點在每個軸上的相交情況

我想寫一個簡單的遊戲，通過點擊時環（不斷變大和變小）在靜止環內進行評分，但我無法弄清楚如何檢測當兩個節點相交時或當移動環位於靜止環內時。如果某人在兩個節點大小相同的情況下點擊，或者如果移動節點位於固定節點內，有人可以向我展示如何添加分數。檢測2個節點在每個軸上的相交情況

import SpriteKit 
import GameplayKit 

class GameScene: SKScene { 

    var Circle = SKSpriteNode() 
    var Circle2 = SKSpriteNode() 

    var GameStarted:Bool = false 

    var Path = UIBezierPath() 
    var run1 = false 
    var called = true 
    var intersected = false 


    override func didMove(to view: SKView) { 
     Circle = SKSpriteNode(imageNamed: "Circle") 
     Circle.size = CGSize(width: 100, height: 100) 
     Circle.position = CGPoint(x: self.frame.midX, y: self.frame.midY) 
     self.addChild(Circle) 
     Circle2 = SKSpriteNode(imageNamed: "Circle2") 
     Circle2.size = CGSize(width: 760, height: 760) 
     Circle2.position = CGPoint(x: self.frame.midX, y: self.frame.midY) 
     self.addChild(Circle2) 
     Circle.zPosition = 0.1 
     Circle2.zPosition = 0.2 
     var path = UIBezierPath(arcCenter: CGPoint(x: 15, y: 15), radius: CGFloat(10), startAngle: 0, endAngle: CGFloat(2*Double.pi), clockwise: true) 
     UIColor.blue.setStroke()  
    } 



    func scaleCircle2(){ 
     let duration = 5.0 
     let scaleAction2 = SKAction.scale(to: CGSize(width: 760, height: 760), duration: TimeInterval(duration)) 
     let scaleAction = SKAction.scale(to: CGSize(width: 15, height: 15), duration: TimeInterval(duration)) 
     let pulse = SKAction.sequence([scaleAction,scaleAction2]) 
     let forever = SKAction.repeatForever(pulse) 
     Circle2.run(forever) 


    } 



    func scaleCircleUP(){ 
     let duration2 = 0.5 
     let initialsize = 100 
     let scaleAction3 = SKAction.scale(to: CGSize(width: initialsize + 100, height: initialsize + 100), duration: TimeInterval(duration2)) 
     Circle.run(scaleAction3) 

    } 



    override func touchesBegan(_ touches: Set<UITouch>, with event: UIEvent?) { 
     GameStarted = true 
     if GameStarted == true{ 
      callCircle2() 
     } 
    } 


    func callCircle2(){ //makes sure scaleCircle2 isn't called twice 
     if called == true{ 
      scaleCircle2() 
     } 
     called = false 
    } 


}

來源

2017-08-05 Johnny

當確定一個圓形物體是否處於另一個較大的圓形物體，只需比較它們的半徑與它們的中心之間的距離的差的絕對值。

extension CGPoint { 
    func distanceTo(_ p:CGPoint) -> CGFloat { 
     return sqrt(pow((p.x - x), 2) + pow((p.y - y), 2)) 
    } 
} 

let dist = Float(Circle.position.distanceTo(Circle2.position)) 
let radiusDiff = fabsf(Float((Circle.size.width - Circle2.size.width)) 
if dist < radiusDiff { 
    // smaller circle is in larger circle 
}

在你的情況，好像你從來沒有把他們的來歷，你知道哪些對象將是「小」之一，簡單地比較它們的半徑。

來源

2017-08-05 03:35:47

檢測2個節點在每個軸上的相交情況

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