2013-03-25 104 views
5

我想製作一個視圖,但我得到一個重複的列名錯誤。如果我單獨運行select查詢,那麼查詢返回如下結果:獲取SQL錯誤:ORA-00957:重複的列名稱,同時創建視圖

SELECT distinct app.APP_REF_NO, app.APP_STATUS, app.APP_DT, app.ATTEND_STAFF, 
       app.ATTEND_BRANCH, app.PRODUCT_TYPE, cust.CUST_ID, 
       cust.APP_JOINT_T, cust.ID1_TYPE, cust.ID1, cust.ID2_TYPE, 
       cust.ID2, cust.FIRST_NAME, cust.LAST_NAME, cust.FULL_NAME, 
       cust.FULL_NAME_CAP, cust.DOB, fac.FACILITY_NO, fac.PRODUCT_TYPE, 
       fac.PRODUCT_CODE, fac.MAIN_PROD_IND, fac.AMT_APPLIED 
FROM 
    LOSA_APP app 
LEFT JOIN 
    LOSA_CUST cust 
ON 
    cust.APP_REF_NO = app.APP_REF_NO 
LEFT JOIN 
    LOSA_FACILITIES fac 
ON 
    fac.APP_REF_NO = app.APP_REF_NO 
LEFT JOIN 
    OS_CURRENTSTEP STEP 
ON 
    STEP.REF_ID = app.APP_REF_NO 
    WHERE (app.APP_STATUS ='P' OR app.APP_STATUS ='T' OR 
     ((app.APP_STATUS='R' OR app.APP_STATUS='S') AND STEP.STEP_NAME='011')); 

此查詢正常工作。但是當我嘗試運行它作爲視圖時:

CREATE VIEW basit_test1 AS 
SELECT distinct app.APP_REF_NO, app.APP_STATUS, app.APP_DT, app.ATTEND_STAFF, 
       app.ATTEND_BRANCH, app.PRODUCT_TYPE, cust.CUST_ID, 
       cust.APP_JOINT_T, cust.ID1_TYPE, cust.ID1, cust.ID2_TYPE, 
       cust.ID2, cust.FIRST_NAME, cust.LAST_NAME, cust.FULL_NAME, 
       cust.FULL_NAME_CAP, cust.DOB, fac.FACILITY_NO, fac.PRODUCT_TYPE, 
       fac.PRODUCT_CODE, fac.MAIN_PROD_IND, fac.AMT_APPLIED 
FROM 
    LOSA_APP app 
LEFT JOIN 
    LOSA_CUST cust 
ON 
    cust.APP_REF_NO = app.APP_REF_NO 
LEFT JOIN 
    LOSA_FACILITIES fac 
ON 
    fac.APP_REF_NO = app.APP_REF_NO 
LEFT JOIN 
    OS_CURRENTSTEP STEP 
ON 
    STEP.REF_ID = app.APP_REF_NO 
    WHERE (app.APP_STATUS ='P' OR app.APP_STATUS ='T' OR 
     ((app.APP_STATUS='R' OR app.APP_STATUS='S') AND STEP.STEP_NAME='011')); 

然後我得到重複的列名稱錯誤。爲什麼我得到這個錯誤?

回答

12

你有兩個product_type列:

fac.PRODUCT_TYPE 

app.PRODUCT_TYPE 

你應該別名其中例如一個

app.PRODUCT_TYPE app_prod_type 
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