創建sql查詢以在時間範圍內獲取重複列值

Question

有人可以幫助我處理此查詢嗎？我想所有的customer_id的其中重複24小時

SELECT 
    O.Order_No, O.Customer_ID, O.DateOrdered, O.IPAddress, 
    C.FirstName, C.LastName, CD.nameoncard 
FROM 
    Order_No O 
INNER JOIN 
    CardData CD ON O.card_id = CD.id 
INNER JOIN 
    Customers C ON O.customer_id = C.customer_id 
ORDER BY 
    O.order_no desc 

增加更多的細節不止一次的結果.. 客戶ID XX因此，假設訂單于04/23下午2:30和2日再次訂單在同一天04/23下午5:30與同一客戶Id xx一起發出。

我想查詢返回我的客戶ID XX

感謝

Answer 1

select Customer_ID, CAST(DateOrdered as Date) DateOrdered, count(*) QTDE 
from Order_No 
group by Customer_ID, CAST(DateOrdered as Date) 
having count(*) > 1 

要得到誰擁有第一一個後發出訂單的客戶，那麼你可以使用下面的查詢：

select distinct A.Customer_ID 
from Order_No A 
inner join (select Customer_ID, min(DateOrdered) DateOrdered from Order_No group by Customer_ID) B 
    on A.Customer_ID = B.Customer_ID 
    and A.DateOrdered - B.DateOrdered <= 1 
    and A.DateOrdered > B.DateOrdered 

SQL Fiddle

要獲得有不止一個數量級的期間發行不超過24h或等於隨時爲所有客戶

select distinct A.Customer_ID 
from Order_No A 
inner join Order_No B 
    on A.Customer_ID = B.Customer_ID 
    and A.DateOrdered > B.DateOrdered 
    and A.DateOrdered - B.DateOrdered <= 1 

SQL Fiddle

Answer 2

自連接：

SELECT distinct O.Customer_ID 
FROM 
Order_No O 
inner join Order_No o2 
on o.customerID = o2.customerID 
    and datediff(hour, o.DateOrdered, o2.DateOrdered) between 0 and 24 
and o.Order_No <> o2.Order_No 

這將返回所有CUSTOMER_IDS在任何24小時的時間內都有多個訂單。

編輯添加匹配記錄不應該是相同的記錄的連接標準。應該返回同時放置兩個不同訂單的客戶，而不是放置一個訂單的客戶。