A pandas.DataFrame
可以直接從字典中構建,因此您只需將my_dict
傳遞給pandas.DataFrame
構造函數(即pandas.DataFrame(my_dict)
)即可。例如:
import pandas
from collections import OrderedDict
import numpy as np
m = 10
n = 5
index = pandas.date_range('1/1/2015', periods=m, freq='D')
my_dict = OrderedDict()
for i in range(1, n+1):
my_dict['var_%d' % i] = pandas.Series(np.random.randn(index.shape[0]), index=index)
print(pandas.DataFrame(my_dict))
var_1 var_2 var_3 var_4 var_5
2015-01-01 0.562952 0.708099 0.488981 -1.360356 -0.036179
2015-01-02 -0.481410 0.604777 0.233426 -0.784103 1.879795
2015-01-03 1.188333 0.299547 -0.578365 0.882410 0.919328
2015-01-04 -1.002273 0.794856 -0.527205 1.474524 -0.798646
2015-01-05 -0.025225 2.246476 -0.460735 0.272014 -0.061749
2015-01-06 -1.304233 1.204737 0.040275 0.293035 0.831555
2015-01-07 -0.934804 0.922393 0.633133 1.064837 -0.154307
2015-01-08 0.440650 0.235624 0.765399 0.306628 -0.274465
2015-01-09 1.637787 -0.158231 -0.643112 -1.128660 0.393349
2015-01-10 0.145501 -0.667916 1.094961 -1.669178 0.447021
您可以添加樣本和期望的輸出嗎?因爲對我而言,如果'concat' OrderedDict' – jezrael
。@ Pat,請返回'TypeError:無法連接非NDFrame對象',請添加數據以及您之後的輸出。爲什麼使用有序字典? – Merlin
'pandas.DataFrame(my_dict)'應該這樣做。 – JaminSore