HAML和迭代的XML

Question

我試圖生成一個XML文件。我有一些標記，重複數字，像這樣：

 
# necessary XML namespace and metadata stuff... 

%img{:src => "Foo002.jpg#full"}/ 
%img{:src => "Foo003.jpg#full"}/ 
%img{:src => "Foo004.jpg#full"}/ 
%img{:src => "Foo005.jpg#full"}/ 
# and so on for a few hundred lines 

%img{:src => "Foo435.jpg#full"}/ 

我給「富」和（在這種情況下435）結束號碼作爲參數。我如何去告訴HAML這樣做？

感謝

編輯：忘了提，前導零是很重要的。

Answer 1

- 2.upto(435) do |n| 
    %img{:src => "Foo%03d.jpg#full" % n} 

或

- (2..435).each do |n| 
    %img{:src => "Foo%03d.jpg#full" % n} 

證明：

phrogz$ haml 
!!! XML 
%root 
    - 2.upto(10) do |n| 
    %img{ src:"Foo%03d.jpg" % n } 
^D 

<?xml version='1.0' encoding='utf-8' ?> 
<root> 
    <img src='Foo002.jpg' /> 
    <img src='Foo003.jpg' /> 
    <img src='Foo004.jpg' /> 
    <img src='Foo005.jpg' /> 
    <img src='Foo006.jpg' /> 
    <img src='Foo007.jpg' /> 
    <img src='Foo008.jpg' /> 
    <img src='Foo009.jpg' /> 
    <img src='Foo010.jpg' /> 
</root>