迭代和數組

Question

我怎樣重複9次，併產生三個數組是這樣的：

1 a 
2 b 
3 c 
["a","b","c"] 

4 d 
5 e 
6 f 
["d","e","f"] 

7 g 
8 h 
9 i 
["g","h","i"] ? 
------------------------------------- 
1.upto(9) do 
xxx = gets.chomp 
    wn << xxx 
if wn.length ==3 
puts wn.inspect 

end 
end 
------------------------------------ 

我得到以下輸出：

a 
b 
c 
["a", "b", "c"] 
d 
e 
f 
g 
h 
i 

不是我希望:(

Answer 1

結果

一個簡單的解決方案：

a1 = [] 
a2 = [] 
a3 = [] 
1.upto(9) do |i| 
    if a1.empty? || a1.size < 3 
    a1 << gets.chomp! 
    elsif a2.size < 3 
    a2 << gets.chomp! 
    else 
    a3 << gets.chomp! 
    end 
end 
puts a1 
puts a2 
puts a3 

創建3個數組，重複9次，創建條件來填充它們。

Answer 2

你必須迭代嗎？你總是可以打破長你的字符串，像這樣：

"abcdefghi".scan(/.{3}/).map{|i| i.split('')} # => [["a", "b", "c"], ["d", "e", "f"], ["g", "h", "i"]] 

如果你真的必須遍歷：

1.upto(9) do 
xxx = gets.chomp 
wn << xxx 
if wn.length % 3 == 0 
    puts wn.inspect 
    end 
end 

Answer 3

我覺得嵌套循環是給你一個乾淨的解決方案。

a = [[],[],[]] 
3.times do |i| 
    3.times { |j| a[i][j] = gets.strip } 
    puts a[i].inspect 
end