2017-08-01 72 views
3

我的以下問題建立在這個帖子上提出@jbaums解決方案:Global Raster of geographic distances如何基於網格細胞子集柵格值

爲了再現例子的目的,我有距離到的柵格數據集最近的海岸線:

library(rasterVis); library(raster); library(maptools) 
data(wrld_simpl) 

# Create a raster template for rasterizing the polys. 
r <- raster(xmn=-180, xmx=180, ymn=-90, ymx=90, res=1) 
# Rasterize and set land pixels to NA 
r2 <- rasterize(wrld_simpl, r, 1) 
r3 <- mask(is.na(r2), r2, maskvalue=1, updatevalue=NA) 
# Calculate distance to nearest non-NA pixel 
d <- distance(r3) # if claculating distances on land instead of ocean: d <- distance(r3) 
# Optionally set non-land pixels to NA (otherwise values are "distance to non-land") 
d <- d*r2 
levelplot(d/1000, margin=FALSE, at=seq(0, maxValue(d)/1000, length=100),colorkey=list(height=0.6), main='Distance to coast (km)') 

的數據是這樣的: output plot

從這裏,我需要子集距離柵格(d),或創建一個新的光柵,僅包含細胞距離海岸線不到200公里。我試圖使用getValues()來確定值爲< = 200(如下所示)的單元格,但目前爲止沒有成功。誰能幫忙?我在正確的軌道上嗎?

#vector of desired cell numbers 
my.pts <- which(getValues(d) <= 200) 
# create raster the same size as d filled with NAs 
bar <- raster(ncols=ncol(d), nrows=nrow(d), res=res(d)) 
bar[] <- NA 
# replace the values with those in d 
bar[my.pts] <- d[my.pts] 

回答

3

我認爲這是你在找什麼,你可以把一個光柵喜歡這裏矩陣右後你d <- d*r2行:

d[d>=200000]<-NA 
levelplot(d/1000, margin=FALSE, at=seq(0, maxValue(d)/1000, length=100),colorkey=list(height=0.6), main='Distance to coast (km)') 

(如果你忘了:在單位是米所以門檻應該是200000,而不是200)

+0

太棒了!有用。謝謝@Ouistiti! – fabfab