定時器倒計時只運行一次而不是循環之後？

Question

每個while循環運行它創建另一個錶行和顯示相關的數據的時候，我要顯示在每行的列倒數計時器（展示時間流逝）。我的下面的腳本只運行一次。你有另一個想法如何做到這一點或做些什麼？我在php while循環內寫了下面的代碼，但只運行一次。請幫助

<script> 
counter=0; 
</script> 
<?php 
$count=0; 
while($rowp = $resultp->fetch_assoc()) { 
echo <td><p id='demo",$count,"'></p></td> 
?> 
<script> 
var countDownDate = new Date("<?php echo $enterytime1; ?>").getTime(); 

// Update the count down every 1 second 
var x = setInterval(function() { 

    // Get todays date and time 
    var now = new Date().getTime(); 

    // Find the distance between now an the count down date 
    var distance = now - countDownDate; 

    // Time calculations for days, hours, minutes and seconds 
    var days = Math.floor(distance/(1000 * 60 * 60 * 24)); 
    var hours = Math.floor((distance % (1000 * 60 * 60 * 24))/(1000 * 60 * 60)); 
    var minutes = Math.floor((distance % (1000 * 60 * 60))/(1000 * 60)); 
    var seconds = Math.floor((distance % (1000 * 60))/1000); 

    // Output the result in an element with id="demo" 
    document.getElementById("demo" + counter).innerHTML = hours + "h " + minutes + "m " + seconds + "s "; 

    // If the count down is over, write some text 
    if (distance < 0) { 
     clearInterval(x); 
     document.getElementById("demo").innerHTML = "EXPIRED"; 
    } 
}, 1000); 
</script> 
<?php } 
?> 

Answer 1

是你必須爲所有列創建新的倒計時

Answer 2

可能是你，如果條件是true - 倒數日期>現在 - 和它終止間隔。

Answer 3

我猜測它會直接過期的吧？你有錯誤的順序。它應該是周圍的其他方法：

VAR距離=倒數日期 - 現在;

Answer 4

我取代php代碼的日期和我改變了distance計算。試試這個，如果有任何變化，然後讓我知道

var countDownDate = new Date(2017, 2, 10, 12, 9, 40, 0).getTime(); 
 
counter = 0; 
 
// Update the count down every 1 second 
 
var x = setInterval(function() { 
 

 
    // Get todays date and time 
 
    var now = new Date().getTime(); 
 

 
    // Find the distance between now an the count down date 
 
    var distance = countDownDate - now; 
 
    // If the count down is over, write some text 
 
    if (distance < 0) { 
 
    clearInterval(x); 
 
    document.getElementById("demo").innerHTML = "EXPIRED"; 
 
    } 
 
    // Time calculations for days, hours, minutes and seconds 
 
    var days = Math.floor(distance/(1000 * 60 * 60 * 24)); 
 
    var hours = Math.floor((distance % (1000 * 60 * 60 * 24))/(1000 * 60 * 60)); 
 
    var minutes = Math.floor((distance % (1000 * 60 * 60))/(1000 * 60)); 
 
    var seconds = Math.floor((distance % (1000 * 60))/1000); 
 
    counter++; 
 
    // Output the result in an element with id="demo" 
 
    var newDiv = document.createElement("div"); 
 
    newDiv.setAttribute("id", "demo" + counter); 
 
    var node = document.createTextNode(days + "days " + hours + "h " + minutes + "m " + seconds + "s "); 
 
    newDiv.appendChild(node); 
 
    if (document.getElementById("demo" + counter) != null) { 
 
    document.getElementById("demo" + counter).innerHTML = days + "days " + hours + "h " + minutes + "m " + seconds + "s "; 
 
    } else { 
 
    document.body.appendChild(newDiv); 
 
    } 
 
    if (counter > 10) 
 
    counter = 0; 
 

 
}, 1000);

div { 
 
    border: 1px black solid; 
 
}

<div id='demo'></div>