有如圖中所示的立體投影兩點:如何通過兩點繪製一個圓(直徑末端)?
這些點被認爲是在一個圓的dimeter的端點。如何繪製一個通過這兩點的圓圈?
代碼用於上述情節:
import matplotlib.pylab as plt
from mpl_toolkits.basemap import Basemap
import numpy as np
from scipy.interpolate import splev, splrep
# create instance of basemap, note we want a south polar projection to 90 = E
myMap = Basemap(projection='spstere',boundinglat=0,lon_0=180,resolution='l',round=True,suppress_ticks=True)
# set the grid up
gridX, gridY = 10.0, 15.0
parallelGrid = np.arange(-90.0,90.0,gridX)
meridianGrid = np.arange(-180.0,180.0,gridY)
# draw parallel and meridian grid, not labels are off. We have to manually create these.
myMap.drawparallels(parallelGrid,labels=[False,False,False,False])
myMap.drawmeridians(meridianGrid,labels=[False,False,False,False],labelstyle='+/-',fmt='%i')
# plot azimuth labels, with a North label.
ax = plt.gca()
ax.text(0.5,1.025,'N',transform=ax.transAxes,horizontalalignment='center',verticalalignment='bottom',size=25)
for para in np.arange(gridY,360,gridY):
x= (1.1*0.5*np.sin(np.deg2rad(para)))+0.5
y= (1.1*0.5*np.cos(np.deg2rad(para)))+0.5
ax.text(x,y,u'%i\N{DEGREE SIGN}'%para,transform=ax.transAxes,horizontalalignment='center',verticalalignment='center')
summerAzi = np.array([0, 360])
summerAlt = np.array([40, 4])
summerX, summerY = myMap(summerAzi, -summerAlt)
summerX_new = np.linspace(summerX.min(), summerX.max(),30)
summerY_smooth = splev(summerX_new, splrep(summerX, summerY, k=1))
myMap.plot(summerX_new, summerY_smooth, 'g')
myMap.plot(summerX, summerY, 'go')
plt.show()
兩點可以定義無限多的圈,你談論的投影空間圓(正如我們看到的)或圓的數學空間(正在表示的數據) –
@NickT;你是對的。我更新了這個問題。這些點是圓的直徑的終點。 – haccks
由於投影,它不工作來計算線的中點,並使用'circ = plt.Circle((myX,myY),radius = myRad)' – beroe