SQL查詢小於或等於16小時30分鐘？

Question

我有以下SQL，

SELECT dims_branchcode, 
     dims_documentname, 
     dims_branchname, 
     Count(dims_documentname) AS NoofRequestWithinCutoff, 
     track.sentdate 
FROM track 
     INNER JOIN td_wf_dims394 
       ON track.documentno = td_wf_dims394.sno 
WHERE (track.indexcardname = 'TD_WF_DIMS394' 
     AND track.sender = 0 
     AND Datepart(hh, senttime) <= 16) 
GROUP BY dims_branchcode, 
      dims_branchname, 
      dims_documentname, 
      sentdate 
ORDER BY track.sentdate 

這是16小時工作很大。但我需要16小時30分鐘如何指定小時和分鐘

Answer 1

加入其中，990是條件（16 * 60）+ 30分鐘

AND DATEDIFF(mi, DATEADD(dd, 0, DATEDIFF(dd, 0, senttime)), senttime)<=990 

代替

AND Datepart(hh, senttime) <= 16 

用示例數據檢查：

declare @tbl as table(dts datetime) 

insert into @tbl values 
('2012-01-07 17:27'), 
('2012-01-07 16:27'), 
('2012-02-22 11:36') 

select * From @tbl 

--condition datepart(hh, dts)<=16 and datepart(minute, dts)<=30, which doesnot include the 3rd row 
select * From @tbl where datepart(hh, dts)<=16 and datepart(minute, dts)<=30 

--gives the desired result 
select * From @tbl where DATEDIFF(mi, DATEADD(dd, 0, DATEDIFF(dd, 0, dts)), dts)<=990