0
編碼社交網絡應用程序和Im有一些問題。我只會問其中一人，因爲我不知道這個論壇的規則，即我是否可以發佈多個問題。我正在學習PHP，正如我的代碼一樣。 我有一個表的用戶，有一個名爲pal_array的字段，其中包含您的好友的用戶的user_id。我的例子，我的朋友陣列有2個user_id的。如何在PHP中查詢數組並返回每個元素的單個行/項目
我希望能夠查詢所有的用戶的朋友，並能夠顯示他們的細節，如拇指圖片，名稱等，我不知道如何正確。
我從pals.php代碼：
<?php
//Establish the Web Intersect Profile Interaction Token here
if(!isset($_SESSION['wipit']))//Check to see if session wipit is set yet
{
session_register('wipit');//Be sure to register the session if it is not yet set
}
$thisRandNum = rand(9999999999999,999999999999999999);
$_SESSION['wipit'] = base64_encode($thisRandNum);
?>
<script type="text/javascript" charset="utf-8">
//jquery functionality for toggling member interaction containers
function toggleInteractContainers(x)
{
if($('#'+x).is(":hidden"))
{
$('#'+x).slideDown(200);
}else
{
$('#'+x).hide();
}
$('.interactContainers').hide();
}
// Pal accepting
var palRequestURL = "request_as_pal.php";
var thisRandNum = "<?php echo $thisRandNum; ?>";
function acceptPalRequest (x) {
$.post(palRequestURL,{ request: "acceptPal", reqID: x, thisWipit: thisRandNum } ,function(data) {
$("#req"+x).html(data).show();
});
}
function denyPalRequest (x) {
$.post(palRequestURL,{ request: "denyPal", reqID: x, thisWipit: thisRandNum } ,function(data) {
$("#req"+x).html(data).show();
});
}
// End Pal accepting
// Pal removal
function removeAsPal(a,b) {
$("#remove_pal_loader").show();
$.post(palRequestURL,{ request: "removePal", mem1: a, mem2: b, thisWipit: thisRandNum } ,function(data) {
$("#remove_friend").html(data).show().fadeOut(12000);
});
}
// End Pal removal
</script>
<?php require_once('Connections/connections.php'); ?>
<?php
//query username
$user_id = $_SESSION['UserSession'];
mysql_select_db($database_connections, $connections);
$query_user_info = "SELECT username FROM users WHERE user_id='$user_id'";
$user_info = mysql_query($query_user_info, $connections) or die(mysql_error());
$row_user_info = mysql_fetch_assoc($user_info);
//code for displaying all your pals
$query_pal_array = "SELECT pal_array FROM users WHERE user_id='$user_id'";
$pal_array_result = mysql_query($query_pal_array, $connections) or die(mysql_error());
$row_pal_array = mysql_fetch_assoc($pal_array_result);
$pal_array = $row_pal_array['pal_array'];
$palList = "";
if($pal_array !="")
{
$palArray = explode(",",$pal_array);
$palCount = count($palArray);
$palArray = array_slice($palArray,0,15);
$i = 0;//how many times we loop over
foreach($palArray as $key =>$array_value)
{
$i++;
//increment by one
$palList = "$array_value";
}
}
else
{
$palCount = "0";
}
?>
<table width="500" border="0">
<tr>
<td height="20"><div class="heading_text_18"><?php echo $row_user_info ['username']; ?>'s pals <?php echo $palCount ?></div> </td>
</tr>
<tr>
<td class="interactionLinksDiv" align="right" style="border:none;"><a href="#" onclick="return false"
onmousedown="javascript: toggleInteractContainers('pal_requests');">Pal Requests</a></td>
</tr>
<tr>
<td height="5"></td>
</tr>
</table>
<div class="interactContainers" id="pal_requests">
<?php
//container for accepting/rejecting pal requests
$pal_requests = "SELECT * FROM pal_requests WHERE mem2='$user_id' ORDER BY pal_request_id ASC LIMIT 50";
$pal_request_query = mysql_query($pal_requests) or die(mysql_error());
$pal_request_num_rows = mysql_num_rows($pal_request_query);
if($pal_request_num_rows < 1)
{
echo ' You have no Pal requests at this time.';
exit();
}
else
{
while($row_pal_query = mysql_fetch_array($pal_request_query))
{
$request_id = $row_pal_query["pal_request_id"];
$mem1 = $row_pal_query["mem1"];
$query_user = "SELECT user_first_name, user_last_name, picture_thumb_url FROM users LEFT JOIN picture ON users.user_id = picture.user_id
AND picture.avatar=1 WHERE users.user_id='$mem1' LIMIT 1";
$user_info = mysql_query($query_user, $connections) or die(mysql_error());
while ($row = mysql_fetch_array($user_info)){ $requesterFirstName = $row["user_first_name"]; $requesterLastName = $row["user_last_name"]; }
{
if(!empty($row["picture_thumb_url"]))
{
$avatar = '<a href="user_view.php?user_id2=' . $mem1 . '"><img src="/NNL/User_Images/' . $row["picture_thumb_url"] . '" width="50" height="50" border="0"/></a>';
}
else
{
$avatar = '<a href="user_view.php?user_id2=' . $mem1 . '"><img src="/NNL/Style/Images/default_avatar.png" width="50" height="50" border="0"/></a>';
}
echo '<hr />
<table width="100%" cellpadding="5">
<tr>
<td width="17%" align="left"><div style="overflow:hidden; height:50px;">'. $avatar .'</div></td>
<td width="83%"><a class="ordinary_text_12_blue "href="user_view.php?user_id2=' . $mem1 . '">'. $requesterFirstName .' '. $requesterLastName .'</a>
wants to be your Pal<br /><br />
<span id="req' . $request_id . '">
<a class="ordinary_text_12" href="#" onclick="return false" onmousedown="javascript:acceptPalRequest(' . $request_id . ');" >Accept</a>
OR
<a class="ordinary_text_12" href="#" onclick="return false" onmousedown="javascript:denyPalRequest(' . $request_id . ');" >Deny</a>
</span></td>
</tr>
</table>';
}
}
}
?>
</div>
<?php
//get pal avatars
$query_pal_info = "SELECT users.user_id, user_first_name, user_last_name, username, picture_thumb_url, avatar FROM users LEFT JOIN picture ON users.user_id = picture.user_id
AND picture.avatar=1 WHERE users.user_id = $array_value";
$pal_info = mysql_query($query_pal_info , $connections) or die(mysql_error());
$totalRows_pal_info = mysql_num_rows($pal_info);
echo $totalRows_pal_info;
echo "\n<table>";
$i = 5;
while ($row_pal_info = mysql_fetch_assoc($pal_info))
{
if($i==5) echo "\n\t<tr>";
$thumbnail_user = $row_pal_info['picture_thumb_url'] != '' ? $row_pal_info['picture_thumb_url'] : '../Style/Images/default_avatar.png';
echo "<td width='100' height='100' align='center' valign='middle'><a href = 'user_view.php?user_id2=$array_value'>
<img src='/NNL/User_Images/$thumbnail_user' border='0'/></a></td>\n";
$i--;
if($i==0) {
echo "\n\t</tr>\n\t<tr>";
$i = 5;
}
}
if($i!=5) echo "\n\t\t<td colspan=\"$i\"></td>\n\t</tr>";
echo "\n</table>";
?>
接近底部，我有這個疑問
$query_pal_info = "SELECT users.user_id, user_first_name, user_last_name, username, picture_thumb_url, avatar FROM users LEFT JOIN picture ON users.user_id = picture.user_id
AND picture.avatar=1 WHERE users.user_id = $array_value";
變量$ array_value保持好朋友的USER_ID的數組。我將如何展示個人好友？我也有一個問題，爲什麼在我的interactContainers div下面的東西不會顯示。
在此先感謝
感謝您的回覆Drackir。 – 2011-02-01 18:52:26