將多行SQL查詢推送到單個PHP數組項目

Question

我現在有一個腦屁。我從數據庫中提取問題和可能的答案，以動態生成使用PHP和MySQL的測驗。下面是輸出我得到：

Response id: 3 Question id: 1 Question: What is my middle name? Title: How Well Do You Know Michael 
    Array (
     [0] => Array (
      [r_id] => 3 
      [question_id] => 1 
      [question] => What is my middle name? 
      [title] => How Well Do You Know Michael)) 
    Array (
     [0] => Array (
      [0] => 1 
      [1] => Abe) 
     [1] => Array (
      [0] => 2 
      [1] => Andrew) 
     [2] => Array (
      [0] => 3 
      [1] => Andre) 
     [3] => Array (
      [0] => 4 
      [1] => Anderson)) 

從這個PHP腳本：

// Grab the question data from the database to generate the form 
    $query = "SELECT qr.response_id AS r_id, qr.question_id, q.question, quiz.title " . 
     "FROM quiz_response AS qr " . 
     "INNER JOIN question AS q USING (question_id) " . 
     "INNER JOIN quiz USING (quiz_id) " . 
     "WHERE qr.user_id = '" . $_SESSION['user_id'] . "'"; 
    $data = mysqli_query($dbc, $query) or die("MySQL error: " . mysqli_error($dbc) . "<hr>\nQuery: $query"); 
    $questions = array(); 
    while ($row = mysqli_fetch_array($data, MYSQL_ASSOC)) { 
     echo 'Response id: ' . $row['r_id'] . 'Question id: ' . $row['question_id'] . ' Question: ' . $row['question'] . ' Title: ' . $row['title'] . '<br />'; 
     array_push($questions, $row); 
     // Pull up the choices for each question 
     $query2 = "SELECT choice_id, choice FROM question_choice " . 
     "WHERE question_id = '" . $row['question_id'] . "'"; 
     $data2 = mysqli_query($dbc, $query2); 
     $choices = array(); 
     while ($row2 = mysqli_fetch_array($data2, MYSQL_NUM)) 
      array_push($choices, $row2); 
    } 
    print_r($questions); 
    print_r($choices); 

不過，我會非常喜歡有$選擇數組中只有一個項目，而不是4個獨立的項目。例如，我想要的選擇數組如下所示：

Array (
    [0] => Array (
     [0] => 1 
     [1] => Abe 
     [2] => 2 
     [3] => Andrew 
     [4] => 3 
     [5] => Andre 
     [6] => 4 
     [7] => Anderson) 

我的問題：**雖然我已經從'

while ($row2 = mysqli_fetch_array($data2, MYSQL_NUM)) 
      array_push($choices, $row2); 

四個獨立的行`反正是有？將它們全部推到數組$選擇的同一項目**

Answer 1

替換此：

array_push($choices, $row2); 

隨着

$choices[0][] = $row2[0]; 
$choices[0][] = $row2[1]; 

無論如何，我認爲沒有數組中的1個元素的數組會更有用。你爲什麼不這樣做？

$choices[] = $row2[0]; 
$choices[] = $row2[1]; 

我最後的評論是，我會去你的當前選項（行排列，每排爲包含的那些列），因爲它更接近數據的真正代表方式。