從外部鏈接獲取文件並存儲到本地服務器

Question

我需要從外部鏈接獲取圖像文件並存儲到本地文件夾中。

我已經使用以下：

$value1 = "https://images.airlist.com/0008459/Listing/129128/3350520160227084506.JPG%3Fv=1?v=1"; 

$img_file = file_get_contents(str_replace("?v=1","",$value1)); 
$file_handler = fopen($file_loc,'w'); 
if(fwrite($file_handler,$img_file)== false) 
    { 
      echo 'error'; 
    } 
    fclose($file_handler); 
    } 

圖像被存儲在一個格式，如：

3308420160227084509.JPG％3Fv = 1-50x50.jpg％3fv = 1

Answer 1

我會做這樣的事情：

$url = "https://images.airlist.com/0008459/Listing/129128/3350520160227084506.JPG%3Fv=1?v=1"; 
$file = explode('?', $url)[0]; // get everything on the left site from the ? 
$file = explode('%', $file)[0]; // get everything on the left site from % 
$filename = basename($file); // get only the filename 
$fileContent = file_get_contents($url); // get image content 
file_put_contents($filename, $fileContent); // write image content to filename 

Answer 2

你一小時前沒有回覆我的評論，但我會假設你想下載https://images.airlist.com/0008459/Listing/129128/3350520160227084506.JPG%3Fv=1‌​?v=1和保存它作爲3350520160227084506.JPG。

<?php 

$value1 = "https://images.airlist.com/0008459/Listing/129128/3350520160227084506.JPG%3Fv=1?v=1"; 

// Take the basename (3350520160227084506.JPG%3Fv=1?v=1) 
// And remove anything starting from either a percent sign (%) or a question mark (?) 
$fileName = preg_replace('~[%?].*$~', '', basename($value1)); 

// $fileName = string(23) "3350520160227084506.JPG" 

file_put_contents($fileName, file_get_contents($value1));