如何解決解析錯誤：語法錯誤，意外 '$查詢'（T_VARIABLE）

Question

<?php 
include ("checklogin.php") 


    $query = "select * from student"; 


    if($query_run =mysql_query($query)) 
    { 
     echo "<table border='1' align= 'center' 
      <tr> 
       <th colspan= '11'> Student Lists</th> 
      </tr> 
      <tr> 
       <th> ID </th> 
       <th> Username </th> 
       <th> Name </th> 
       <th> Address </th> 
       <th> Contact Number </th> 
       <th> Identity Card </th> 
       <th> License Number </th> 
       <th> Email </th> 
       <th> Gender </th> 
       <th> Update </th> 
       <th> Delete </th> 

      </tr>"; 

     while($fetch= mysql_fetch_array($query_run)) 
     { 
      echo"<tr> 
        <td>".$fetch['id']."</td> 
        <td>".$fetch['username']."</td> 
        <td>".$fetch['name']."</td> 
        <td>".$fetch['address']."</td> 
        <td>".$fetch['cn']."</td> 
        <td>".$fetch['ic']."</td> 
        <td>".$fetch['ln']."</td> 
        <td>".$fetch['email']."</td> 
        <td>".$fetch['sex']."</td> 
     <td><a href='updatestudent.php?id=$fetch[id]& 
     username=$fetch[username]& 
     name=$fetch[name]& 
     address=$fetch[address]& 
     cn=$fetch[cn]& 
     ic=$fetch[ic]& 
     ln=$fetch[ln]& 
     email=$fetch[email]& 
     sex=$fetch[sex]'> 
       <input type ='button' name='update' 
       value='update'></a></td> 
       <td><a href='deletestudent.php?id=[id]'> 
       <input type='button' name='delete' 
       value='delete'</a></td> 
      </tr>"; 
     } 

    } 
    else 
    { 
     echo "<center>"; 
     echo "invalid query"; 
     echo "</center>"; 
    } 

>

Answer 1

if($query_run =mysql_query($query)) 

是錯誤的。改爲：

if($query_run ==mysql_query($query))