優化SQL查詢以獲得特定答案的計數

Question

我正在用10個問題創建一個調查。所有問題都有5個可能的答案，其值爲1-5。數據存儲在每個用戶一行的數據庫中。每個問題都有一個答案。

爲了使條形圖的回答每一個問題，我目前檢索的行數，其中一個特定列的值等於一個特定的可能的答案：

SELECT COUNT(*) AS `records_found` FROM (`antworten`) WHERE `frage1` = 1 
SELECT COUNT(*) AS `records_found` FROM (`antworten`) WHERE `frage1` = 2 
SELECT COUNT(*) AS `records_found` FROM (`antworten`) WHERE `frage1` = 3 
SELECT COUNT(*) AS `records_found` FROM (`antworten`) WHERE `frage1` = 4 
SELECT COUNT(*) AS `records_found` FROM (`antworten`) WHERE `frage1` = 5 
SELECT COUNT(*) AS `records_found` FROM (`antworten`) WHERE `frage2` = 1 
SELECT COUNT(*) AS `records_found` FROM (`antworten`) WHERE `frage2` = 2 
SELECT COUNT(*) AS `records_found` FROM (`antworten`) WHERE `frage2` = 3 
SELECT COUNT(*) AS `records_found` FROM (`antworten`) WHERE `frage2` = 4 
SELECT COUNT(*) AS `records_found` FROM (`antworten`) WHERE `frage2` = 5 
(...) 

這將生成如下圖形：http://i.imgur.com/SESJ8.png

這可能很愚蠢，並且可能有更好的方法來檢索所需的數據。我無法想出它，有人可以幫助我嗎？ ：） 謝謝。

Answer 1

可能：

SELECT 1 As FrageNummer, frage1 As Frage, count(*) As Anzahl 
FROM antworten 
GROUP BY frage1 
UNION 
SELECT 2 As FrageNummer, frage2 As Frage, count(*) As Anzahl 
FROM antworten 
GROUP BY frage2 

等。

當然這會更容易查詢，如果「fragen」被放進行而不是列，即具有這樣的數據：

id | quartalid | frage_nr | frage 
--------------------------------- 
9 |   5 |  1 |  5 
9 |   5 |  2 |  5 
9 |   5 |  3 |  2 

等

然後，你可以簡單地查詢像這樣

SELECT frage_nr, frage, count(*) 
FROM antworten 
GROUP BY frage_nr, frage 

Answer 2

對於單一的問題，你可以使用

select frage1, count(*) as `records_found` 
    from antworten 
group by frage1 
order by frage1 

或相似。可能有一種方法可以立即使用多維數據集和樞軸等來完成所有問題，但我不知道它。