編輯:一件事,你也可以,只發送一個信道,而不是兩個......
我不知道這是正確的做法,但我沒有做數據的插入從麥克風, 我猜,你是從麥克風這樣的捕捉你的數據接收,
this.node.onaudioprocess = function(e){
if (!recording) return;
worker.postMessage({
command: 'record',
buffer: [
e.inputBuffer.getChannelData(0),
e.inputBuffer.getChannelData(1)
]
});
}
現在修改成
var oldSampleRate = 44100, newSampleRate = 16000;
this.node.onaudioprocess = function(e){
var leftData = e.inputBuffer.getChannelData(0);
var rightData = e.inputBuffer.getChannelData(1);
leftData = interpolateArray(leftData, leftData.length * (newSampleRate/oldSampleRate) );
rightData = interpolateArray(rightData, rightData.length * (newSampleRate/oldSampleRate));
if (!recording) return;
worker.postMessage({
command: 'record',
buffer: [
leftData,
rightData
]
});
}
function interpolateArray(data, fitCount) {
var linearInterpolate = function (before, after, atPoint) {
return before + (after - before) * atPoint;
};
var newData = new Array();
var springFactor = new Number((data.length - 1)/(fitCount - 1));
newData[0] = data[0]; // for new allocation
for (var i = 1; i < fitCount - 1; i++) {
var tmp = i * springFactor;
var before = new Number(Math.floor(tmp)).toFixed();
var after = new Number(Math.ceil(tmp)).toFixed();
var atPoint = tmp - before;
newData[i] = linearInterpolate(data[before], data[after], atPoint);
}
newData[fitCount - 1] = data[data.length - 1]; // for new allocation
return newData;
};