我無法使用urllib2打開一個特定的網址。同樣的方法適用於其他網站,如「http://www.google.com」,但不適用於此網站(該網站在瀏覽器中也顯示正常)。urllib2返回404爲瀏覽器顯示罰款的網站
我簡單的代碼:
from BeautifulSoup import BeautifulSoup
import urllib2
url="http://www.experts.scival.com/einstein/"
response=urllib2.urlopen(url)
html=response.read()
soup=BeautifulSoup(html)
print soup
誰能幫我做工作?
這是錯誤我:
Traceback (most recent call last):
File "/Users/jontaotao/Documents/workspace/MedicalSchoolInfo/src/AlbertEinsteinCollegeOfMedicine_SciValExperts/getlink.py", line 12, in <module>
response=urllib2.urlopen(url);
File "/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/urllib2.py", line 126, in urlopen
return _opener.open(url, data, timeout)
File "/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/urllib2.py", line 400, in open
response = meth(req, response)
File "/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/urllib2.py", line 513, in http_response
'http', request, response, code, msg, hdrs)
File "/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/urllib2.py", line 432, in error
result = self._call_chain(*args)
File "/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/urllib2.py", line 372, in _call_chain
result = func(*args)
File "/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/urllib2.py", line 619, in http_error_302
return self.parent.open(new, timeout=req.timeout)
File "/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/urllib2.py", line 400, in open
response = meth(req, response)
File "/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/urllib2.py", line 513, in http_response
'http', request, response, code, msg, hdrs)
File "/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/urllib2.py", line 438, in error
return self._call_chain(*args)
File "/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/urllib2.py", line 372, in _call_chain
result = func(*args)
File "/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/urllib2.py", line 521, in http_error_default
raise HTTPError(req.get_full_url(), code, msg, hdrs, fp)
urllib2.HTTPError: HTTP Error 404: Not Found
謝謝
什麼是你的錯誤? –
停止在行尾添加分號。這是Python。 – FogleBird
我的錯是關於獲取參數,但我認爲不是你的問題 –