大家好。我的目標是當我想點擊ListView中的特定項目時,它會打開一個我編程的新活動。例如:當我點擊「João」時,我希望它打開一個名爲Joao的類。我試過使用簡單的代碼,但它不起作用。當我從ListView中點擊João的名字時,什麼也沒有發生。如何ListView使用onClick打開一個新的活動?
這是我的代碼,我使用:
public class Searchsort extends Activity {
private ListView lv1;
private EditText ed;
private String lv_arr[]={"John","Mary","Carl","Rose","Charlie","Allan", "João"};
private ArrayList<String> arr_sort= new ArrayList<String>();
int textlength=0;
/** Called when the activity is first created. */
@Override
public void onCreate(Bundle icicle) {
super.onCreate(icicle);
setContentView(R.layout.main);
lv1 = (ListView)findViewById(R.id.ListView01);
ed = (EditText)findViewById(R.id.EditText01);
// By using setAdpater method in listview we an add string array in list.
lv1.setAdapter(new ArrayAdapter<String>(this,android.R.layout.simple_list_item_1 , lv_arr));
ed.addTextChangedListener(new TextWatcher() {
public void afterTextChanged(Editable s) {
}
public void beforeTextChanged(CharSequence s, int start, int count, int after) {
}
public void onTextChanged(CharSequence s, int start, int before, int count) {
textlength=ed.getText().length();
arr_sort.clear();
for(int i=0;i<lv_arr.length;i++) {
if(textlength<=lv_arr[i].length()) {
if(ed.getText().toString().equalsIgnoreCase((String) lv_arr[i].subSequence(0, textlength))) {
arr_sort.add(lv_arr[i]);
}
}
}
lv1.setAdapter(new ArrayAdapter<String> (Searchsort.this,android.R.layout.simple_list_item_1 , arr_sort));
}
});
}
public void onListItemClick(ListView parent, View v, int position, long id) {
if ("João".equals(lv_arr[position])) {
Intent myIntent = new Intent(Searchsort.this, Joao.class);
startActivity(myIntent);
}
}
}
什麼是使用一個開關或者如果條件的問題? – 2012-07-25 06:23:19