這是我項目中的一段代碼,我需要這個線程結束直到最後才轉到最後一個Log.i()並完成該函數。finish在活動繼續之前的線程動作
public void delay3Seconds(final String txt1, final String txt2, final String s, final Intent i)
{
//keepMoving= false;
counter= 3;
secondsBool= true;
if(!errorMonitor)
{
Log.i("Main.delay3Seconds()", s+" in 3 seconds");
new Thread()
{
public void run()
{
while(secondsBool)
{
try {
Thread.sleep(1500);
}
catch (InterruptedException e){e.printStackTrace();}
if(!errorMonitor)
{
handler.post(new Runnable()
{
public void run()
{
final DialogFragment loadDF= new RecDialog(MainActivity.this, txt1, txt2, s+(counter--)+" שניות", null, false, true, ll.getWidth(), ll.getHeight());
loadDF.show(getSupportFragmentManager(), "RecDialog");
dialog.dismiss();
dialog= loadDF;
if(counter == 0)
secondsBool= false;
}
});
}
else
secondsBool= false;
}
if(!errorMonitor)
{
handler.post(new Runnable()
{
public void run()
{
dialog.dismiss();
if (i.resolveActivity(getPackageManager()) != null)
{
Log.i("Main.delay3Seconds()", "resolveActivity != null");
setResolveNotFail(true);
Log.i("Main.delay3Seconds()", "resolveNotFail = "+resolveNotFail);
startActivity(i);
}
else
{
Log.i("Main.delay3Seconds()", "resolveActivity == null");
setResolveNotFail(false);
Log.i("Main.delay3Seconds()", "resolveNotFail = "+resolveNotFail);
}
}
});
}
}
}.start();
}
Log.i("Main.delay3Seconds()", "(end) resolveNotFail = "+resolveNotFail);
}
我不知道該怎麼做。我嘗試使用synchronized(),但我可能使用它是錯誤的,因爲該函數首先完成自己,然後只有線程工作,同時到活動。
我將不勝感激就如何做..
這是不可能的,你開始一個新的線程。原始線程繼續運行並退出該功能。你究竟想達到什麼目的? – Francesc