奇怪的編譯器錯誤的解析器代碼

Question

Parser.h

enum { PLUS, MINUS, DIVIDE, MULTIPLY, NUMBER, END } type; 

int token; 

/* parsing functions */ 
void parse_token (void); 

Parser.c

的錯誤

parser.c:14:6: warning: conflicting types for ‘parse_token’ [enabled by default] 
parser.c:11:2: note: previous implicit declaration of ‘parse_token’ was here 
parser.c: In function ‘parse_token’: 
parser.c:16:2: warning: passing argument 2 of ‘strchr’ makes integer from pointer without a cast [enabled by default] 
/usr/include/string.h:235:14: note: expected ‘int’ but argument is of type ‘char *’ 
parser.c:17:3: error: ‘type’ undeclared (first use in this function) 
parser.c:17:3: note: each undeclared identifier is reported only once for each function it appears in 
parser.c:17:10: error: ‘NUMBER’ undeclared (first use in this function) 
parser.c:19:2: warning: passing argument 2 of ‘strchr’ makes integer from pointer without a cast [enabled by default] 
/usr/include/string.h:235:14: note: expected ‘int’ but argument is of type ‘char *’ 
parser.c:20:10: error: ‘PLUS’ undeclared (first use in this function) 
parser.c:22:2: warning: passing argument 2 of ‘strchr’ makes integer from pointer without a cast [enabled by default] 
/usr/include/string.h:235:14: note: expected ‘int’ but argument is of type ‘char *’ 
parser.c:23:10: error: ‘MINUS’ undeclared (first use in this function) 
parser.c:25:2: warning: passing argument 2 of ‘strchr’ makes integer from pointer without a cast [enabled by default] 
/usr/include/string.h:235:14: note: expected ‘int’ but argument is of type ‘char *’ 
parser.c:26:10: error: ‘DIVIDE’ undeclared (first use in this function) 
parser.c:28:2: warning: passing argument 2 of ‘strchr’ makes integer from pointer without a cast [enabled by default] 
/usr/include/string.h:235:14: note: expected ‘int’ but argument is of type ‘char *’ 
parser.c:29:10: error: ‘MULTIPLY’ undeclared (first use in this function) 
parser.c:32:10: error: ‘END’ undeclared (first use in this function) 
parser.c: In function ‘show_error’: 
parser.c:40:2: warning: incompatible implicit declaration of built-in function ‘exit’ [enabled by default] 

我徹底班博ozled。 。？:(

任何幫助

Answer 1

一個你得到它編譯（通過包括頭，作爲L uchian Grigore說），你會發現你不能在常量字符串上做strcat()。

常量字符串被分配在只讀存儲器中，無法修改。即使你可以修改它，你也會覆蓋其他內存。

Answer 2

你不包括你的頭，所以沒有辦法對翻譯單元瞭解的type和token聲明

您需要：

#include "Parser.h" 

在執行文件的開頭