從數據庫中刪除字符串中的特定字符選擇

Question

我已經將數據存儲在像下面這樣的單元格中：RP1=8, RP2=6, RP3=8, RP4=7有沒有一種方法可以在我調用該數據時去掉RP1=部分而僅剩下值？

$row = $result->fetch_assoc(); 
echo $row['rp1']; 
echo $row['rp2']; 
echo $row['rp3']; 
echo $row['rp4']; 

print_r（$ row）;

Array ([id] => 1 [dashboardId] => 1 [memberId] => 1 [rp1] => RP1=8 [rp2] => RP2=6 [rp3] => RP3=8 [rp4] => RP4=7 [teamId] => 1) 

Answer 1

的一種方式，以羅馬：

$row = $result->fetch_assoc(); 
#replace can go over all entries here, it is specific enuff 
$row = array_map(function($a){return preg_replace('#^(RP[0-9]+=)#','',trim($a));},$row); 
echo $row['rp1']; 
echo $row['rp2']; 
echo $row['rp3']; 
echo $row['rp4'];