從字符串中刪除字符串

String startTag = "<sessionid>"; 
String endTag = "</sessionid>";          
if (startTag.equalsIgnoreCase("<sessionid>") && 
    endTag.equalsIgnoreCase("</sessionid>")) 
{ 
    int startLocation = strResponse.indexOf(startTag); 
    int endLocation = strResponse.indexOf(endTag); 
    Log.i("StartLocation", ""+startLocation); 
    Log.i("EndLocation", ""+endLocation); 
    String session_id = strResponse.substring(startLocation, endLocation); 
    ConstantData.session_id =session_id; 
    Log.i("SessionId", ""+session_id); 
}

我得到session_id = <sessionid>32423jhoijhoijh;所以我想刪除<sessionid>。任何幫助將不勝感激。從字符串中刪除字符串

來源

2011-04-04 shripal

嘗試String session_id = strResponse.substring（startLocation + 11，endLocation）;這裏是11的長度是 – mudit 2011-04-04 12:44:18

確切的重複[如何刪除一部分字符串？]（http://stackoverflow.com/questions/5538271/how-can-i-remove-a-part-of-a -string） – 2011-04-04 12:52:43

請將答案標誌授予爲您提供合適解決方案的人員。 – JJD 2012-11-11 16:00:54

int startLocation = strResponse.indexOf(startTag) + string length of startTag

來源

2011-04-04 12:38:52

取"<sessionid>"長度爲您的startIndex代替的indexOf。

來源

2011-04-04 12:38:54 chris

只是刪除字符串中的第11個字母或字符：

String startTag = "<sessionid>"; 
String endTag = "</sessionid>";          
if (startTag.equalsIgnoreCase("<sessionid>") && 
    endTag.equalsIgnoreCase("</sessionid>")) 
{ 
    int startLocation = strResponse.indexOf(startTag); 
    int endLocation = strResponse.indexOf(endTag); 
    Log.i("StartLocation", ""+startLocation); 
    Log.i("EndLocation", ""+endLocation); 
    String session_id = strResponse.substring(startLocation, endLocation); 
    session_id = session_id.substring(11, session_id.length()); 
    ConstantData.session_id =session_id; 
    Log.i("SessionId", ""+session_id); 
}

來源

2011-04-04 12:38:59

一個可以嘗試的正則表達式太;

String str = "<sessionid>ABCDEFGH</sessionid>"; 
    str = str.replaceFirst("<sessionid>(\\S+)</sessionid>", "$1");

來源

2011-04-04 13:00:39 harism

從字符串中刪除字符串

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