mysql的分隔符工作在MySQL，但不是在PHP

Question

我有這樣的代碼（我取代MySQL的測試目的的變量）在MySQL的phpmyadmin &工作因而追加-1 -2 -3等的course_no：

drop trigger if exists change_course_no; 

delimiter | 

CREATE TRIGGER change_course_no BEFORE INSERT ON hybrid_locked 
FOR EACH ROW BEGIN 
declare original_course_no varchar(50); 
declare course_no_counter int; 
set original_course_no = new.course_no; 
set course_no_counter = 1; 


while exists (select true from hybrid_locked where course_no = new.course_no) do 
set new.course_no = concat(original_course_no, '-', course_no_counter); 
set course_no_counter = course_no_counter + 1; 
end while; 

END; 

| 

delimiter ; 


insert into hybrid_locked (
requestor_name, academic_unit, 
instructor_name, instructor_email, tel_number, creds, more_instructors, 
course_name, program_name, term, course_no, classroom, comments, online_exam, participants, hybrid_past1, hybrid_past2, hybrid_past3, date_requested, 

main_date_start, main_date_end, main_time_start, main_time_end, 
sec_date_start, sec_date_end, sec_time_start, sec_time_end, 
unique_date1, unique_date1_time_start, unique_date1_time_end, 
unique_date2, unique_date2_time_start, unique_date2_time_end 
) 

values ('Smith', 'test', 
'Joe', 'joe@gmail.com', '555-555-5555', 'no', '', 
'Physics', '', 'summer', 'TEST101', '1025', '', 'yes', '10', 
'unsure', 'unsure', 'unsure', '2016-12-05', 

'2016-12-06', '2016-12-29', '17:45:00', '19:45:00', 
'0000-00-00', '0000-00-00', '00:00:00', '00:00:00', 
'0000-00-00', '00:00:00', '00:00:00', 
'0000-00-00', '00:00:00', '00:00:00' 
); 

但是，當我把它添加到我的PHP腳本失敗，出現錯誤：

您的SQL語法錯誤;檢查與您的MySQL服務器版本相對應的手冊，以找到在'delimiter |附近使用的正確語法CREATE TRIGGER change_course_no BEFORE INSERT ON的3號線

這是在PHP形式的代碼hybrid_locked FO」：

$query_hybrid = 

" 
drop trigger if exists change_course_no; 

delimiter | 

CREATE TRIGGER change_course_no BEFORE INSERT ON hybrid_locked 
FOR EACH ROW BEGIN 
declare original_course_no varchar(50); 
declare course_no_counter int; 
set original_course_no = new.course_no; 
set course_no_counter = 1; 


while exists (select true from hybrid_locked where course_no = new.course_no) do 
set new.course_no = concat(original_course_no, '-', course_no_counter); 
set course_no_counter = course_no_counter + 1; 
end while; 

END; 

| 

delimiter ; 


insert into hybrid_locked (
requestor_name, academic_unit, 
instructor_name, instructor_email, tel_number, creds, more_instructors, 
course_name, program_name, term, course_no, classroom, comments, online_exam, participants, hybrid_past1, hybrid_past2, hybrid_past3, date_requested, 

main_date_start, main_date_end, main_time_start, main_time_end, 
sec_date_start, sec_date_end, sec_time_start, sec_time_end, 
unique_date1, unique_date1_time_start, unique_date1_time_end, 
unique_date2, unique_date2_time_start, unique_date2_time_end 
) 

values ('$requestor_name', '$academic_unit', 
'$instructor_name', '$instructor_email', '$tel_number', '$creds', '$more_instructors', '$course_name', '$program_name', '$term', '$course_no', '$classroom', '$comments', '$online_exam', '$participants', '$hybrid_past1', '$hybrid_past2', '$hybrid_past3', '$date_requested', 

'$main_date_start', '$main_date_end', '$main_time_start', '$main_time_end', 
'$sec_date_start', '$sec_date_end', '$sec_time_start', '$sec_time_end', 
'$unique_date1', '$unique_date1_time_start', '$unique_date1_time_end', 
'$unique_date2', '$unique_date2_time_start', '$unique_date2_time_end' 
)"; 

我不明白我失蹤的PHP腳本？

謝謝， 克里斯

Answer 1

你可能根本不應該從內PHP反正這樣做，但如果你這樣做，你應該用什麼mysqli_multi_query

bool mysqli_multi_query (mysqli $link , string $query) Executes one or multiple queries which are concatenated by a semicolon.

其他方法不允許你在一個API調用中執行多個查詢。