從這裏舉個例子: http://www.cplusplus.com/reference/algorithm/sort/使用類:排序()
可見
struct myclass {
bool operator() (int i,int j) { return (i<j);}
} myobject;
int main() {
int myints[] = {32,71,12,45,26,80,53,33};
std::vector<int> myvector (myints, myints+8); // 32 71 12 45 26 80 53 33
// using object as comp
std::sort (myvector.begin(), myvector.end(), myobject); //(12 26 32 33 45 53 71 80)
}
這工作得很好,但是我想使用的,而不是結構類。那麼,我做的是:
CardComparer類:
bool CardComparer::operator() (Card* firstCard, Card* secondCard) {
this->firstCard = firstCard;
this->secondCard = secondCard;
if (firstCard->GetRank() == secondCard->GetRank()) {
return firstCard->GetSuit() > secondCard->GetSuit();
}
else {
return firstCard->GetRank() > secondCard->GetRank();
}
}
,這是主要的:
CardComparer* compare;
compare = new CardComparer();
sort(cards.begin(), cards.end(), compare->operator());
我得到這個長的錯誤:
hand.cpp: In member function 'void Hand::AddCard(Card*)':
hand.cpp:60:54: error: no matching function for call to 'sort(std::vector<Card*>::iterator, std::vector<Card*>::iterator, <unresolved overloaded function type>)'
hand.cpp:60:54: note: candidates are:
In file included from /usr/include/c++/4.7/algorithm:63:0,
from hand.cpp:4:
/usr/include/c++/4.7/bits/stl_algo.h:5463:5: note: template<class _RAIter> void std::sort(_RAIter, _RAIter)
/usr/include/c++/4.7/bits/stl_algo.h:5463:5: note: template argument deduction/substitution failed:
hand.cpp:60:54: note: candidate expects 2 arguments, 3 provided
In file included from /usr/include/c++/4.7/algorithm:63:0,
from hand.cpp:4:
/usr/include/c++/4.7/bits/stl_algo.h:5499:5: note: void std::sort(_RAIter, _RAIter, _Compare) [with _RAIter = __gnu_cxx::__normal_iterator<Card**, std::vector<Card*> >; _Compare = bool (CardComparer::*)(Card*, Card*)]
/usr/include/c++/4.7/bits/stl_algo.h:5499:5: note: no known conversion for argument 3 from '<unresolved overloaded function type>' to 'bool (CardComparer::*)(Card*, Card*)'
我不能」噸真的找到一個解決方案,因爲如果我修改該示例,並保持它作爲一個結構它工作正常,但不工作時,我轉換它我nto類。
結構*是*一類。你的意思是當你需要一個對象時你試圖使用一個指針(然後是一個成員函數指針)。如示例所示,使用類/結構類型的對象。 – 2013-04-24 02:14:38