無法添加引導選項卡爲PHP代碼

Question

如果我添加此引導標籤成HTML代碼，它完美的作品：

<ul class="nav nav-tabs"> 
    <li class="active"><a href="#hello" data-toggle="tab">Hello</a></li> 
    <li><a href="#empty" data-toggle="tab">Empty</a></li> 
</ul> 

    <div class="tab-content"> 
     <div class="tab-pane active" id="hello"> 
     <h3>Hello my Friend!</h3> 
     <p>hello</p> 
     </div><!-- @end #hello --> 

     <div class="tab-pane" id="empty"> 
     <h3>Just gonna be empty...</h3> 

     <p>Yup. Nothin' here.</p> 
     </div><!-- @end #empty --> 
    </div> 

不過，在這些自來水，我需要連接到我的數據庫，所以顯示的一些信息，我代碼是：

<ul class="nav nav-tabs"> 
     <li class="active"><a href="#facilities" data-toggle="tab">Facilities</a></li> 
     <li><a href="#fee" data-toggle="tab">Course Fee</a></li> 
</ul> 
<div class="tab-content"> 
    <div class="tab-pane active" id="facilities"> 
     <h3>Just gonna be empty...</h3>   
     <p>Yup. Nothin' here.</p> 
     <?php echo "<table>"; 
      $userpic = '<img src="images/user.png"/>'; 
      while ($roww = mysqli_fetch_array($usercomment)){ 
       $cm_fac = $roww['facilities']; 
       $name = $roww['UserName']; 
       $time = $roww['CmtDate']; 
       echo '<tr>'; 
        echo '<td>'; 
         //i put some info here as table 
        echo '</td>'; 
       echo '</tr>'; 
      } 
     echo "</table>"; 
     ?> 
    </div><!-- end of facilities--> 

    <div class="tab-pane" id="fee"> 
     <h3>Hello my Friend!</h3> 
     <p>hello</p> 
     <?php echo "<table>"; 
      $userpic = '<img src="images/user.png"/>'; 
      while ($roww = mysqli_fetch_array($usercomment)){ 
       $cm_fee = $roww['fee']; 
       $name = $roww['UserName']; 
       $time = $roww['CmtDate']; 
       echo '<tr>'; 
        echo '<td>'; 
         //some info here too 
        echo '</td>'; 
       echo '</tr>'; 
      } 
     echo "</table>"; 
     ?> 
    </div><!-- end of fee--> 

</div> <!--end of tab-content--> 

但它不起作用。任何人都可以告訴我我的問題？ 謝謝你的時間。

Answer 1

Thôinóitiếngviệtđi。 ：d。數據庫數據庫是什麼？ - Bạnmuốngoilạihàmwhile ($roww = mysqli_fetch_array($usercomment)) khiđảgọinó1lầnởtrênphảikhông。 Bạnđổitêncáibiến$ rowwởdưới= $ roww1thửcoi，víbiến$ rowwtrùngvớiởtrên。

Answer 2

你也許可以試試這個：

<div class="tab-pane" id="fee"> 
    <h3>Hello my Friend!</h3> 
    <p>hello</p> 

<!-- open the 'while' --> 
    <?php 
    while ($roww = mysqli_fetch_array($usercomment)){ 
     $cm_fac = $roww['facilities']; 
     $name = $roww['UserName']; 
     $time = $roww['CmtDate']; 
    ?> 

<!-- your table --> 
    <table> 
    <tr> 
     <td> 
     <?php echo "your data here"; ?> 
     </td> 
    </tr> 
    </table> 

<?php } ?> <!-- close the 'while' here --> 
</div> 

Answer 3

• 查詢的檢查結果。
• 您可以使用$roww = mysqli_fetch_array($usercomment, MYSQLI_ASSOC);來獲取數據。